Chapter 12.4, Problem 1P

Find the minimum, first quartile, median, third quartile, and maximum of each dataset.

220 150 200 180 320 330 300

To determine

Find minimum , first quartile , median , third quartile , and maximum of the given data set.

Answer to Problem 1P

Minimum = 150

First quartile = 180

Median = 220

Third quartile = 320

Maximum = 330

Explanation of Solution

Given:

220 , 150 , 200 , 180 , 320 , 330 , 300

Calculation:

Arrange the data in ascending order:

150 , 180 , 200 , 220 , 300 , 320 , 330

The minimum is 150.

The first quartile is the median of the lower half of the data set.

Since the total entries are 7, which is odd , So, the lower half is the first $\frac{7-1}{2}=3$ entries.

So , the first quartile is the 2^nd entry = 180

Median = The middle entry since there are 7 entries , which is odd = $\frac{7+1}{2}=4^{th}$ entry = 220

The third quartile is the median of the upper half of the data set.

Since the total entries are 7, which is odd , So, the upper half is the last $\frac{7-1}{2}=3$ entries.

So , the third quartile is the 6^th entry = 320

The maximum is 330.