Concerning alkane and cycloalkane boiling points, the incorrect ones has to be chosen from the given options. Concept Introduction: Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula. Alkanes are linear chain saturated hydrocarbons and cycloalkanes are cyclic carbon chain saturated hydrocarbons. They both occur naturally. Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water. Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density. Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about 30 ° C for every carbon atom that is added to the chain. The continuous alkanes which contain one to four carbon atoms are gases at room temperature. The continuous chain alkanes that contain five to seventeen carbon atoms are liquids at room temperature. The continuous chain alkanes that contain more than eighteen carbon atoms are solids at room temperature. When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms. Cycloalkanes have more boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.

Question

Want to see the full answer?

Answer 1

Question

Chapter 12.16, Problem 2QQ

Interpretation Introduction

Interpretation:

Concerning alkane and cycloalkane boiling points, the incorrect ones has to be chosen from the given options.

Concept Introduction:

Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.

Alkanes are linear chain saturated hydrocarbons and cycloalkanes are cyclic carbon chain saturated hydrocarbons. They both occur naturally.

Alkanes and cycloalkanes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkanes and cycloalkanes do not get solubilized in water. In other words, alkanes and cycloalkanes are insoluble in water.

Regarding density, alkanes and cycloalkanes have density lower than water. When alkanes and cycloalkanes are mixed with water, two layers are formed which is a result of insolubility. Alkanes and cycloalkanes are present on top of water layer which is due to lesser density.

Boiling point of alkanes and cycloalkanes increase with an increase in carbon‑chain length or the ring size. When considering the continuous‑chain alkanes, the boiling point of alkanes increases about 30 °C for every carbon atom that is added to the chain. The continuous alkanes which contain one to four carbon atoms are gases at room temperature. The continuous chain alkanes that contain five to seventeen carbon atoms are liquids at room temperature. The continuous chain alkanes that contain more than eighteen carbon atoms are solids at room temperature.

When branching happens in the carbon chain, it lowers the boiling point of alkanes. In simple words, unbranched alkanes have more boiling point than branched alkanes with the same number of carbon atoms.

Cycloalkanes have more boiling point compared to noncyclic alkanes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropane and cyclobutane are gases at room temperature. Cyclopentane to cyclooctane are liquids at room temperature.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Correct each molecule in the drawing area below so that it has the skeletal ("line") structure it would have if it were dissolved in a 0.1 M aqueous solution of HCI. If there are no changes to be made, check the No changes box under the drawing area. No changes. HO Explanation Check NH, 2 W O :□ G ©2025 M unter Accessibility

An expression for the root mean square velocity, vrms, of a gas was derived. Using Maxwell’s velocity distribution, one can also calculate the mean velocity and the most probable velocity (mp) of a collection of molecules. The equations used for these two quantities are vmean=(8RT/πM)1/2 and vmp=(2RT/M)1/2 These values have a fixed relationship to each other.(a) Arrange these three quantities in order of increasing magnitude.(b) Show that the relative magnitudes are independent of the molar mass of the gas.(c) Use the smallest velocity as a reference for establishing the order of magnitude and determine the relationship between the larger and smaller values.

The reaction of solid dimethylhydrazine, (CH3)2N2H2, and liquefied dinitrogen tetroxide, N2O4, has been investigated for use as rocket fuel. The reaction produces the gases carbon dioxide (CO2), nitrogen (N2), and water vapor (H2O), which are ejected in the exhaust gases. In a controlled experiment, solid dimethylhydrazine was reacted with excess dinitrogen tetroxide, and the gases were collected in a closed balloon until a pressure of 2.50 atm and a temperature of 400.0 K were reached.(a) What are the partial pressures of CO2, N2, and H2O?(b) When the CO2 is removed by chemical reaction, what are the partial pressures of the remaining gases?