Explanation Given information: The pull force of an athlete ( P ) on handle A is 100 N. The distance ( x A ) moved by handle A is 30 cm. The velocity ( v A ) of handle A is 3 m/s. Calculation: Sketch the system with distance of cable connecting handle A and weight stack B as in Figure (2). Write total length of cable connecting handle A and weight stack B . x A + 4 y B = constant (1) Here, x A is the length of cable connecting handle A and y B is the length of cable connecting weight stack B . Differentiate Equation (1) with respect to t to write velocity of the blocks. v A + 4 v B = constant (2) Here, v A is the velocity of the block A and v B is the velocity of the weight stack B. Differentiate Equation (2) with respect to t to write acceleration of the blocks. a A + 4 a B = 0 a B = a A 4 (3) Here, a A is the acceleration of block A and a B acceleration of weight stack B . The acceleration of handle A is uniform. Hence use general kinematics equation. Find the acceleration of handle A ( a ) using equation of kinematics: v A 2 = ( v A ) 0 2 + 2 a A [ x A − ( x A ) 0 ] Here, ( v A ) 0 initial velocity of handle A and ( x A ) 0 is the initial distance of handle A . Substitute 3 m/s for v A , 0 for ( v A ) 0 , 30 cm for x A , and 0 for ( x A ) 0

Vector Mechanics for Engineers: Statics and Dynamics

11th Edition

ISBN: 9780073398242

Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek, Phillip J. Cornwell, Brian Self

Publisher: McGraw-Hill Education

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Chapter 12.1, Problem 12.30P

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Find the mass of the weight stack B.

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Vector Mechanics for Engineers: Statics and Dynamics

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Find the mass of the weight stack B .

Solution Summary: The author calculates the system with distance of cable connecting handle A and weight stack B as in Figure (2).

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