World of Chemistry
7th Edition
ISBN: 9780618562763
Author: Steven S. Zumdahl
Publisher: Houghton Mifflin College Div
expand_more
expand_more
format_list_bulleted
Question
Chapter 1.2, Problem 4RQ
Interpretation Introduction
Interpretation: Concepts of a model, an observation, a theory, a law needs to be explained.
Concept Introduction:The scientific method is a systematic way of collecting evidence to support theories/ concepts. This helps to explain the nature around us. In scientific disciplines, the term “model”, “observation”, “theory” and “law” holds different meanings of phenomena.
Expert Solution & Answer
Answer to Problem 4RQ
Model: Chemists use models to try and also explain their observations as they formulate theories.
Observation: Something perceived that causes curiosity is categorized in observation.
Theory: Theory is an explanation of events or observations.
Law: Law is defined as the descriptionof any observed phenomenon.
Explanation of Solution
Model: Model is the most basic element of the scientific method. Model is a representation of a particular phenomenon in the world. For example: Physical model of any experiment.
Observation: Observations are essential in the subject chemistry. Chemists use observations to collect as well as record the data. Based on calculations. For example: Newton observe the apples fall down from the tree.
Theory: Theory is a group of connected ideas or concepts intended to describe something. It involves question- “why” or “how anything/ somethings happens. For example: After this Newton gave a theory that there might be some force, which pull the apples down toward the ground. This theory is known as gravity.
Law: Law summarizes a set of observation about natural phenomena. It is based on hypotheses and evidences. For example: Newton’s law of motion.
Chapter 1 Solutions
World of Chemistry
Ch. 1.1 - Prob. 1RQCh. 1.1 - Prob. 2RQCh. 1.1 - Prob. 3RQCh. 1.1 - Prob. 4RQCh. 1.1 - Prob. 5RQCh. 1.2 - Prob. 1RQCh. 1.2 - Prob. 2RQCh. 1.2 - Prob. 3RQCh. 1.2 - Prob. 4RQCh. 1.3 - Prob. 1RQ
Ch. 1.3 - Prob. 2RQCh. 1.3 - Prob. 3RQCh. 1 - Prob. 1ACh. 1 - Prob. 2ACh. 1 - Prob. 3ACh. 1 - Prob. 4ACh. 1 - Prob. 5ACh. 1 - Prob. 6ACh. 1 - Prob. 7ACh. 1 - Prob. 8ACh. 1 - Prob. 9ACh. 1 - Prob. 10ACh. 1 - Prob. 11ACh. 1 - Prob. 12ACh. 1 - Prob. 13ACh. 1 - Prob. 14ACh. 1 - Prob. 15ACh. 1 - Prob. 16ACh. 1 - Prob. 17ACh. 1 - Prob. 18ACh. 1 - Prob. 1STPCh. 1 - Prob. 2STPCh. 1 - Prob. 3STPCh. 1 - Prob. 4STPCh. 1 - Prob. 5STPCh. 1 - Prob. 6STPCh. 1 - Prob. 7STPCh. 1 - Prob. 8STPCh. 1 - Prob. 9STPCh. 1 - Prob. 10STP
Knowledge Booster
Similar questions
- You have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you manipulated and exploited the acid-base chemistry of one or more of the compounds in your mixture to facilitate their separation into different phases. The key to understanding how liquid- liquid extractions work is by knowing which layer a compound is in, and in what protonation state. The following liquid-liquid extraction is different from the one you performed in Experiment 4, but it uses the same type of logic. Your task is to show how to separate apart Compound A and Compound B. . Complete the following flowchart of a liquid-liquid extraction. Handwritten work is encouraged. • Draw by hand (neatly) only the appropriate organic compound(s) in the boxes. . Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4 and 5. • Box 7a requires the solvent (name is fine). • Box 7b requires one inorganic compound. • You can neatly complete this assignment by hand and…arrow_forwardb) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;' The compound has the ff electronic transitions: 0%o* and no a* 1H NMR Spectrum (CDCl3, 400 MHz) 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm 13C{H} NMR Spectrum (CDCl3, 100 MHz) Solvent 80 70 60 50 40 30 20 10 0 ppm ppm ¹H-13C me-HSQC Spectrum ppm (CDCl3, 400 MHz) 5 ¹H-¹H COSY Spectrum (CDCl3, 400 MHz) 0.5 10 3.5 3.0 2.5 2.0 1.5 1.0 10 15 20 20 25 30 30 -35 -1.0 1.5 -2.0 -2.5 3.0 -3.5 0.5 ppm 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppmarrow_forwardShow work with explanation. don't give Ai generated solutionarrow_forward
- Redraw the flowchartarrow_forwardredraw the flowchart with boxes and molecules written in themarrow_forwardPart I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward
- • Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forwardNonearrow_forward
- Draw the curved-arrow mechanism with the drawings of the molecules, not just abbreviations. -NO₂ Sn, HCl (aq) E D H (CH3CO)₂O -NH2 CH3arrow_forwardWhat is/are the product(s) of the following reaction? Select all that apply. * HI A B C OD OH A B OH D Carrow_forwardIn the image, the light blue sphere represents a mole of hydrogen atoms, the purple or teal spheres represent a mole of a conjugate base. A light blue sphere by itself is H+. Assuming there is 2.00 L of solution, answer the following: The Ka of the left & right solution is? The pH of the left & right solution is? The acid on the left & right is what kind of acid?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY