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(a)
Interpretation:
The
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
The
(b)
Interpretation:
The sum of the
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Propagation: In this stage, two steps are involving hydrogen abstraction and halogen abstraction (no change in the number of free radicals)
(c)
Interpretation:
The reason why both the above reactions from subpart (a) and (b) have same
Concept introduction:
Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.
Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.
Propagation: In this stage, two steps are involving hydrogen abstraction and halogen abstraction (no change in the number of free radicals)
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Chapter 12 Solutions
ORGANIC CHEMISTRY-W/S.G+SOLN.MANUAL
- 9. Draw all of the possible Monochlorination Products that would Result From the Free Radical Chlormation OF 23,4-TRIMethyl Pentane b. Calculate the To Yield For the major • Product given the Following Relative Restritus For 1° 2° and 30 Hydrogens toward Free Radical Chloration 5.0: 38 : 1 30 2° 1° C. what would be the major product in the Free Radical brominator Of the Same Molecule. Explain your Reasoning.arrow_forwardWhat is the complete reaction mechanism for the chlorination of Ethane, C2H6?arrow_forwardA 13C NMR spectrum is shown for a molecule with the molecular formula of C6H100. Draw the structure that best fits this data. 220 200 180 160 140 120100 80 60 40 20 Drawingarrow_forward
- Based on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons. Dept 135 shows peak to be positive at 128.62 and 13.63 Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10. Provide assignment for the provided structurearrow_forwardO Predict the 'H NMR integration ratio for the following structure. IV I. 3 H A II. 1 H III. 2 H IV. 3 H I. 3 H B II. O H III. 2 H IV. 3 H I. 3 H C II. 2 H III. 2 Harrow_forward205. From the definition of the Gibbs free energy, G = H - TS, derive the Gibbs-Helmholtz equation a (or (G)),- =- H T2arrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781285199023Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
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