For the reaction 2 H 2 O ( g ) ⇌ 2 H 2 ( g ) + O 2 ( g ) K = 2.4 × 10 −3 at a given temperature. At equilibrium in a 2.0-L container it is found that [H 2 O ( g )] = 1.1 × 10 − 1 M and [H 2 ( g )] = 1.9 × 10 − 2 M. Calculate the moles of O 2 ( g ) present under these conditions.
For the reaction 2 H 2 O ( g ) ⇌ 2 H 2 ( g ) + O 2 ( g ) K = 2.4 × 10 −3 at a given temperature. At equilibrium in a 2.0-L container it is found that [H 2 O ( g )] = 1.1 × 10 − 1 M and [H 2 ( g )] = 1.9 × 10 − 2 M. Calculate the moles of O 2 ( g ) present under these conditions.
Solution Summary: The author explains that the equilibrium constant value for the stated reaction is given 2.4times 10-3.
K = 2.4 × 10−3 at a given temperature. At equilibrium in a 2.0-L container it is found that [H2O (g)] = 1.1 × 10−1 M and [H2(g)] = 1.9 × 10−2M. Calculate the moles of O2(g) present under these conditions.
Using the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.
Synthesis of Dibenzalacetone
[References]
Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below.
Question 1
1 pt
Question 2
1 pt
Question 3
1 pt
H
Question 4
1 pt
Question 5
1 pt
Question 6
1 pt
Question 7
1pt
Question 8
1 pt
Progress:
7/8 items
Que Feb 24 at
You do not have to consider stereochemistry.
. Draw the enolate ion in its carbanion form.
• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
⚫ Separate multiple reactants using the + sign from the drop-down menu.
?
4
Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)
Chapter 12 Solutions
Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell