The partial pressure values of N 2 , H 2 and NH 3 at a particular temperature are given. The value of the equilibrium constant ( K p ) for the given reaction is to be calculated. A comment on the equilibrium state for the reaction with the reactants having the given partial pressure values is to be determined. Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. When the equilibrium constant is expressed in terms of pressure, it is represented K p . To determine: The equilibrium constant ( K p ) for the given reaction.
The partial pressure values of N 2 , H 2 and NH 3 at a particular temperature are given. The value of the equilibrium constant ( K p ) for the given reaction is to be calculated. A comment on the equilibrium state for the reaction with the reactants having the given partial pressure values is to be determined. Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. When the equilibrium constant is expressed in terms of pressure, it is represented K p . To determine: The equilibrium constant ( K p ) for the given reaction.
Solution Summary: The author calculates the equilibrium constant (K_p) for the given reaction.
Definition Definition Transformation of a chemical species into another chemical species. A chemical reaction consists of breaking existing bonds and forming new ones by changing the position of electrons. These reactions are best explained using a chemical equation.
Chapter 12, Problem 30E
Interpretation Introduction
Interpretation: The partial pressure values of
N2,
H2 and
NH3 at a particular temperature are given. The value of the equilibrium constant
(Kp) for the given reaction is to be calculated. A comment on the equilibrium state for the reaction with the reactants having the given partial pressure values is to be determined.
Concept introduction: The state when the reactants involved in a chemical reaction and the products formed in the reaction exist in concentrations having no further tendency to change is known as an equilibrium state of the reaction. When the equilibrium constant is expressed in terms of pressure, it is represented
Kp.
To determine: The equilibrium constant
(Kp) for the given reaction.
3. Is 2-methyl-2-propanol a primary, secondary, or tertiary alcohol? Write
out the
structures of 2-methyl-2-propanol and also any oxidation products of 2-
methyl-2-
propanol. If there is more than one oxidation product, give the structure of
each
of the products.
4. 2-Propanol is the IUPAC systematic name of this alcohol. It has a
common name
by which it is much better known (You'll see it in the grocery store or
pharmacy).
Give that common name
5. Aldehydes can be synthesized by the oxidation of. Please choose from
below choices
A. Primary alcohols
B. Secondary alcohols
C. Organic acids
D. Inorganic acids
6. Tertiary alcohol Can undergo oxidation. yes or no. ? If yes then answer the
product.
Finish the reactions
hand written please
Part A
Identify each alcohol as primary, secondary, or tertiary
Drag the appropriate items to their respective bins.
CH₂
H₂C-
-C-OH
HO
CH₂
Primary
Он
OH
CH₂
OH
CCH₂OH
CH₂
сн
Secondary
Tertiary
Reset Help
CH,CH₂
(CH)CHCH,OH CH,CH,CH,CCH,
CHOH
CH₂
Different types of alcohol groups
Alcohol and its reaction:
8. Combing two alcohol molecules below and completing the reaction with
Product .( Hint Reaction called etherification as ether is formed and name the
ether once you complete the reaction.
Hint.:
R-O-H+H-O-RR-O-R
Do the reaction:
CH₂OH + CH₂OH---→
+ H-O-H
9. Write the reaction of formation of alcohol from alkene by adding water:
Addition reaction also called hydration reaction as we are adding water
which occur always in presence of acid
Hint: Break the double bond and add H and OH if symmetrical then
add anywhere if unsymmetrical then follow Markovnikov rule H
should go to that double bone carbon which has more hydrogen
CH2=CH2 + H₂O-→
Chapter 12 Solutions
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