EBK MECHANICS OF MATERIALS
7th Edition
ISBN: 8220102804487
Author: BEER
Publisher: YUZU
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Chapter 1.2, Problem 21P
A 40-kN axial load is applied to a short wooden post that is supported by a concrete footing resting on undisturbed soil. Determine (a) the maximum bearing stress on the concrete footing, (b) the size of the footing for which the average bearing stress in the soil is 145 kPa.
Fig. P1.21
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Assignment 10, Question 4, Problem Book #202
Problem Statement
An ideal Brayton cycle with a two-stage compressor, a two-stage turbine, and a regenerator
operates with a mass flow rate of 25 kg/s. The regenerator cold inlet is at 490 K and its
effectiveness is 60%. Ambient conditions are 90 kPa and 20°C. The intercooler operates at
450 kPa and the reheater operates at 550 kPa. The temperature at the exit of the combustion
chamber is 1,400 K. Heat is removed in the intercooler at a rate of 2.5 MW and heat is added
in the reheater at a rate of 10 MW. Determine the thermal efficiency and the back work
ratio. Use a cold air standard analysis with cp = 1.005 kJ/(kg K) and k = 1.4.
.
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Assignment 10, Question 3, Problem Book #198
Problem Statement
Consider a Brayton cycle with a regenerator. The regenerator has an effectiveness of 75%.
The compressor inlet conditions are 1.2 bar and 300 K and the mass flowrate is 4.5 kg/s. The
compressor outlet pressure is 9 bar. Both the compressor and turbine consist of a single
isentropic stage. What minimum power output must be achieved before the regenerator
begins to have a benefit? Use an air-standard analysis.
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Q-3 Consider an engine operating on the ideal Diesel cycle with air as the
working fluid. The volume of the cylinder is 1200 cm³ at the beginning of the
Compression process, 75 cm³ at the end, and 150 cm³ after the heat addition
process. Air is at 17°c and lookpa at the beginning of the compression proc
ess. Determine @ The pressure at the beginning of the heat rejection
process. the net work per cycle in kjⒸthe mean effective pressur.
Answers @264.3 KN/m² ②0.784 kj or 544-6 kj © 697 KN
19
2
m
Chapter 1 Solutions
EBK MECHANICS OF MATERIALS
Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - Two solid cylindrical rods AB and BC are welded...Ch. 1.2 - A strain gage located at C on the surface of bone...Ch. 1.2 - Two brass rods AB and BC, each of uniform...Ch. 1.2 - Each of the four vertical links has an 8 36-mm...Ch. 1.2 - Link AC has a uniform rectangular cross section 18...Ch. 1.2 - Three forces, each of magnitude P = 4 kN, are...Ch. 1.2 - Link BD consists of a single bar 1 in. wide and 12...
Ch. 1.2 - For the Pratt bridge truss and loading shown,...Ch. 1.2 - The frame shown consists of four wooden members,...Ch. 1.2 - An aircraft tow bar is positioned by means of a...Ch. 1.2 - Two hydraulic cylinders are used to control the...Ch. 1.2 - Determine the diameter of the largest circular...Ch. 1.2 - Two wooden planks, each 12 in. thick and 9 in....Ch. 1.2 - When the force P reached 1600 lb, the wooden...Ch. 1.2 - A load P is applied to a steel rod supported as...Ch. 1.2 - The axial force in the column supporting the...Ch. 1.2 - Three wooden planks are fastened together by a...Ch. 1.2 - A 40-kN axial load is applied to a short wooden...Ch. 1.2 - An axial load P is supported by a short W8 40...Ch. 1.2 - Link AB, of width b = 2 in. and thickness t=14...Ch. 1.2 - Determine the largest load P that can be applied...Ch. 1.2 - Knowing that = 40 and P = 9 kN, determine (a) the...Ch. 1.2 - The hydraulic cylinder CF, which partially...Ch. 1.2 - For the assembly and loading of Prob. 1.7,...Ch. 1.2 - Two identical linkage-and-hydraulic-cylinder...Ch. 1.5 - Two wooden members of uniform rectangular cross...Ch. 1.5 - Two wooden members of uniform rectangular cross...Ch. 1.5 - The 1.4-kip load P is supported by two wooden...Ch. 1.5 - Two wooden members of uniform cross section are...Ch. 1.5 - A centric load P is applied to the granite block...Ch. 1.5 - A 240-kip load P is applied to the granite block...Ch. 1.5 - A steel pipe of 400-mm outer diameter is...Ch. 1.5 - A steel pipe of 400-mm outer diameter is...Ch. 1.5 - A steel loop ABCD of length 5 ft and of 38-in....Ch. 1.5 - Link BC is 6 mm thick, has a width w = 25 mm, and...Ch. 1.5 - Link BC is 6 mm thick and is made of a steel with...Ch. 1.5 - Members AB and BC of the truss shown are made of...Ch. 1.5 - Members AB and BC of the truss shown are made of...Ch. 1.5 - Link AB is to be made of a steel for which the...Ch. 1.5 - Two wooden members are joined by plywood splice...Ch. 1.5 - For the joint and loading of Prob. 1.43, determine...Ch. 1.5 - Three 34-in.-diameter steel bolts are to be used...Ch. 1.5 - Three steel bolts are to be used to attach the...Ch. 1.5 - A load P is supported as shown by a steel pin that...Ch. 1.5 - A load P is supported as shown by a steel pin that...Ch. 1.5 - A steel plate 14 in. thick is embedded in a...Ch. 1.5 - Determine the factor of safety for the cable...Ch. 1.5 - Link AC is made of a steel with a 65-ksi ultimate...Ch. 1.5 - Solve Prob. 1.51, assuming that the structure has...Ch. 1.5 - Each of the two vertical links CF connecting the...Ch. 1.5 - Solve Prob. 1.53, assuming that the pins at C and...Ch. 1.5 - In the structure shown, an 8-mm-diameter pin is...Ch. 1.5 - In an alternative design for the structure of...Ch. 1.5 - Prob. 57PCh. 1.5 - The Load and Resistance Factor Design method is to...Ch. 1 - In the marine crane shown, link CD is known to...Ch. 1 - Two horizontal 5-kip forces are applied to pin B...Ch. 1 - For the assembly and loading of Prob. 1.60,...Ch. 1 - Two steel plates are to be held together by means...Ch. 1 - A couple M of magnitude 1500 N m is applied to...Ch. 1 - Knowing that link DE is 18 in. thick and 1 in....Ch. 1 - A 58-in.-diameter steel rod AB is fitted to a...Ch. 1 - In the steel structure shown, a 6-mm-diameter pin...Ch. 1 - Prob. 67RPCh. 1 - A force P is applied as shown to a steel...Ch. 1 - The two portions of member AB are glued together...Ch. 1 - The two portions of member AB are glued together...
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