Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. You end up with three plants, all which have round peas. From this data, can you tell if the round pea parent plant is homozygous dominant or heterozygous? If the round pea parent plant is heterozygous, what is the probability that a random sample of 3 progeny peas will all be round?

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

100%

Chapter 12, Problem 1VCQ

Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. You end up with three plants, all which have round peas. From this data, can you tell if the round pea parent plant is homozygous dominant or heterozygous? If the round pea parent plant is heterozygous, what is the probability that a random sample of 3 progeny peas will all be round?

Chapter 12, Problem 1VCQ, Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross

Expert Solution & Answer

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Limetown S1E4 Transcript: E n 2025SP-BIO-111-PSNT1: Natu X Natural Selection in insects X + newconnect.mheducation.com/student/todo CA NATURAL SELECTION NATURAL SELECTION IN INSECTS (HARDY-WEINBERG LAW) INTRODUCTION LABORATORY SIMULATION A Lab Data Is this the correct allele frequency? Is this the correct genotype frequency? Is this the correct phenotype frequency? Total 1000 Phenotype Frequency Typica Carbonaria Allele Frequency 9 P 635 823 968 1118 1435 Color Initial Frequency Light 0.25 Dark 0.75 Frequency Gs 0.02 Allele Initial Allele Frequency Gs Allele Frequency d 0.50 0 D 0.50 0 Genotype Frequency Moths Genotype Color Moths Released Initial Frequency Frequency G5 Number of Moths Gs NC - X

Which of the following is not a sequence-specific DNA binding protein? 1. the catabolite-activated protein 2. the trp repressor protein 3. the flowering locus C protein 4. the flowering locus D protein 5. GAL4 6. all of the above are sequence-specific DNA binding proteins

Which of the following is not a DNA binding protein? 1. the lac repressor protein 2. the catabolite activated protein 3. the trp repressor protein 4. the flowering locus C protein 5. the flowering locus D protein 6. GAL4 7. all of the above are DNA binding proteins

Answer 2

Textbook Question

100%

Chapter 12, Problem 1VCQ

Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. You end up with three plants, all which have round peas. From this data, can you tell if the round pea parent plant is homozygous dominant or heterozygous? If the round pea parent plant is heterozygous, what is the probability that a random sample of 3 progeny peas will all be round?

Chapter 12, Problem 1VCQ, Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross

Expert Solution & Answer

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

100%

Chapter 12, Problem 1VCQ

Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. You end up with three plants, all which have round peas. From this data, can you tell if the round pea parent plant is homozygous dominant or heterozygous? If the round pea parent plant is heterozygous, what is the probability that a random sample of 3 progeny peas will all be round?

Chapter 12, Problem 1VCQ, Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross

Expert Solution & Answer

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

100%

Chapter 12, Problem 1VCQ

Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross between a pea plant with wrinkled peas (genotype rr) and a plant of unknown genotype that has round peas. You end up with three plants, all which have round peas. From this data, can you tell if the round pea parent plant is homozygous dominant or heterozygous? If the round pea parent plant is heterozygous, what is the probability that a random sample of 3 progeny peas will all be round?

Chapter 12, Problem 1VCQ, Figure 12.5 In pea plants, round peas (R) are dominant to wrinkled peas (r). You do a test cross

Expert Solution & Answer

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

100%

Answer 6

Textbook Question

100%

Answer 7

Expert Solution & Answer

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Answer 8

Expert Solution & Answer

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Summary Introduction

To write:

The probability that a random sample of 3 progeny peas will be round.

Introduction:

The test cross can be defined as the cross, which is used to determine the genotype of the plants, especially, whether it is heterozygous dominant or homozygous dominant. In case the result of test cross comes as all dominant, then the plant is homozygous dominant, in case the cross shows 1:1 phenotype of dominant: recessive then the plant tested would be heterozygous dominant.

Answer 12

Explanation of Solution

The question says that a round seed pea plant was crossed with recessive (wrinkled seed) pea plant, which gives three plant having round pea seeds.

The given below is the analysis of the heterozygous pea plant and homozygous pea plant with a wrinkled plant.

Biology 2e, Chapter 12, Problem 1VCQ

From the crosses shown above, we can observe that in a test cross, the homozygous dominant plant produces all heterozygous dominant plants and the heterozygous plant produces 50% dominant and 50% recessive.

The transfer of the allele is random, as there is a probability that the plant with homozygous dominant trait would also produce the round seed, the data given in the question is very small. Hence, it cannot be concluded that the parent is homozygous or heterozygous. But, as per the given data one can most probably say it is homozygous.

For a heterozygote plant, the probability of getting one plant having round seed is 50% or ½.

Hence, the probability of getting 3 plant with a round seed with heterozygote plant would be:

probability of getting a round seed ×probability of getting a round seed×probability of getting a round seed=12×12×12=18.

Answer 13

Conclusion

The tested plant can be both homozygous or heterozygous and the probability of getting 3 plant with round seed by the heterozygous plant is 1/8.

Answer 14

Ch. 12 - Figure 12.5 In pea plants, round peas (R) are...Ch. 12 - Figure 12.6 What are the genotypes of the...Ch. 12 - Figure 12.12 What ratio of offspring would result...Ch. 12 - Figure 12.16 In pea plants, purple flowers (P) are...Ch. 12 - Mendel performed hybridizations by transferring...Ch. 12 - Which is one of the seven characteristics that...Ch. 12 - Imagine you are performing a cross involving seed...Ch. 12 - Consider a cross to investigate the pea pod...Ch. 12 - A scientist pollinates a true-breeding pea plant...Ch. 12 - The observable traits expressed by an organism are...

Concept explainers

Videos

Explanation of Solution

Want to see more full solutions like this?

Chapter 12 Solutions

Additional Science Textbook Solutions