sing only the periodic table, predict the most stable ion for Na , Mg , Al , s , Cl , K , Ca , and Ga . Arrange these elements from largest to smallest radius and explain why the radius varies as it does.
sing only the periodic table, predict the most stable ion for Na , Mg , Al , s , Cl , K , Ca , and Ga . Arrange these elements from largest to smallest radius and explain why the radius varies as it does.
sing only the periodic table, predict the most stable ion for
Na
,
Mg
,
Al
,
s
,
Cl
,
K
,
Ca
,
and Ga
. Arrange these elements from largest to smallest radius and explain why the radius varies as it does.
Expert Solution & Answer
Interpretation Introduction
Interpretation:
The most stable ions of Na, Mg, Al, S, Cl, K, Ca, and Ga are to be predicted. The given elements are to be arranged in order of decreasing radii and the reason as to why the radius varies is to be stated.
Concept Introduction:
The gain or loss of electrons from an atom results in the formation of ionic species. The atoms bearing positive and negative charges combine to form an ionic compound. The radii of ions are different as compared to their parent atoms because ions either possess negative charge or positive charge on them.
Answer to Problem 1ALQ
The most stable ions for Na, Mg, Al, S, Cl, K, Ca, and Ga are Na+, Mg2+, Al3+, S2−, Cl−, K+, Ca2+ and Ga3+ respectively. The arrangement of elements in order of decreasing radii on the basis of position of elements in the periodic table is shown below.
K>Ca>Na>Mg>Ga>Al>S>Cl
The atomic radii increase down the group due to increase in the number of shells, whereas it decreases along the period from left to right due to the addition of electrons in the same valence shell.
Explanation of Solution
The ions become stable when they acquire complete octet. The positive and negative value of ion denotes the number of electrons gained or lost. Therefore, the most stable ions for Na, Mg, Al, S, Cl, K, Ca, and Ga are Na+, Mg2+, Al3+, S2−, Cl−, K+, Ca2+ and Ga3+ respectively.
The positively and negatively charged atom is referred to as a cation and an anion respectively.
The arrangement of elements in order of decreasing radii on the basis of position of elements in the periodic table is shown below.
K>Ca>Na>Mg>Ga>Al>S>Cl
The atomic radii increase down the group due to increase in the number of shells, whereas it decreases along the period from left to right due to the addition of electrons in the same valence shell.
Conclusion
The most stable ions for Na, Mg, Al, S, Cl, K, Ca, and Ga are Na+, Mg2+, Al3+, S2−, Cl−, K+, Ca2+ and Ga3+ respectively. The arrangement of elements in order of decreasing radii on the basis of the position of elements in the periodic table is shown below.
K>Ca>Na>Mg>Ga>Al>S>Cl
The atomic radii increase down the group due to increase in the number of shells, whereas it decreases along the period from left to right due to the addition of electrons in the same valence shell.
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Suppose a chemist discovers a new metallic element and names it "Xhaustium" (Xh).Xh exhibits chemical behaviour similar to an alkaline earth.
Xh(s) + F2(g) → XhF2(s)
Lattice energy for XhF2
-2140. kJ/mol
First Ionization energy of Xh
310. kJ/mol
Second Ionization energy of Xh
589 kJ/mol
Electron affinity of F
-327.8 kJ/mol
Bond energy of F2
154 kJ/mol
Enthalpy of sublimation (atomization) of Xh
150. kJ/mol
Use the above data to calculate ΔH°f for Xhaustium fluoride.
Your answer must be accurate and precise to the nearest 1 kJ/mol, as are the given parameters.
Based on the following information calculate the approximate lattice energy of MgCl2.
The radius of Na+ is 1.5 times as large as Mg2+. The lattice energy for NaCl is
787 kJ/mole.
Calculate the lattice energy of NaCl(s) using the following thermodynamic data (all data is in kJ/mol). Note that the data given has been perturbed, so looking up the answer is probably not a good idea.
Na(s)
ΔHsublimation = 88 kJ/mol
Na(g)
Ionization energy = 476 kJ/mol
Cl-Cl(g)
Bond energy = 223 kJ/mol
Cl(g)
Electron affinity = -369 kJ/mol
NaCl(s)
ΔH°f = -431 kJ/mol
____________ kJ/mol
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