The value of equilibrium constant for the given reaction needs to be determined. Concept introduction: The system is said to be in equilibrium if the there is no change in the partial pressure or concentration of reactant and product takes place. For a general reaction as follows: A ( g ) + B ( g ) ⇌ C ( g ) + D ( g ) The expression for the equilibrium constant is represented as follows: K = ( P C ) ( P D ) ( P A ) ( P B ) Here, to calculate the equilibrium constant, the values of partial pressure of all the species in reactant and product side are required. If an equilibrium reaction is reversed, the value of its equilibrium constant gets inversed. If an equilibrium reaction is multiplied by any value, the value will become the power of the equilibrium constant. On adding two equilibrium reactions, the value of their equilibrium constant gets multiplied. On subtracting two equilibrium reactions, the value of their equilibrium constant gets divided.
The value of equilibrium constant for the given reaction needs to be determined. Concept introduction: The system is said to be in equilibrium if the there is no change in the partial pressure or concentration of reactant and product takes place. For a general reaction as follows: A ( g ) + B ( g ) ⇌ C ( g ) + D ( g ) The expression for the equilibrium constant is represented as follows: K = ( P C ) ( P D ) ( P A ) ( P B ) Here, to calculate the equilibrium constant, the values of partial pressure of all the species in reactant and product side are required. If an equilibrium reaction is reversed, the value of its equilibrium constant gets inversed. If an equilibrium reaction is multiplied by any value, the value will become the power of the equilibrium constant. On adding two equilibrium reactions, the value of their equilibrium constant gets multiplied. On subtracting two equilibrium reactions, the value of their equilibrium constant gets divided.
Solution Summary: The author explains that the value of equilibrium constant for a given reaction needs to be determined.
The value of equilibrium constant for the given reaction needs to be determined.
Concept introduction:
The system is said to be in equilibrium if the there is no change in the partial pressure or concentration of reactant and product takes place.
For a general reaction as follows:
A(g)+B(g)⇌C(g)+D(g)
The expression for the equilibrium constant is represented as follows:
K=(PC)(PD)(PA)(PB)
Here, to calculate the equilibrium constant, the values of partial pressure of all the species in reactant and product side are required.
If an equilibrium reaction is reversed, the value of its equilibrium constant gets inversed. If an equilibrium reaction is multiplied by any value, the value will become the power of the equilibrium constant. On adding two equilibrium reactions, the value of their equilibrium constant gets multiplied. On subtracting two equilibrium reactions, the value of their equilibrium constant gets divided.
(f) SO:
Best Lewis Structure
3
e group geometry:_
shape/molecular geometry:,
(g) CF2CF2
Best Lewis Structure
polarity:
e group arrangement:_
shape/molecular geometry:
(h) (NH4)2SO4
Best Lewis Structure
polarity:
e group arrangement:
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
Sketch (with angles):
1.
Problem Set 3b
Chem 141
For each of the following compounds draw the BEST Lewis Structure then sketch the molecule (showing
bond angles). Identify (i) electron group geometry (ii) shape around EACH central atom (iii) whether the
molecule is polar or non-polar (iv)
(a) SeF4
Best Lewis Structure
e group arrangement:_
shape/molecular geometry:
polarity:
(b) AsOBr3
Best Lewis Structure
e group arrangement:_
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
(c) SOCI
Best Lewis Structure
2
e group arrangement:
shape/molecular geometry:_
(d) PCls
Best Lewis Structure
polarity:
e group geometry:_
shape/molecular geometry:_
(e) Ba(BrO2):
Best Lewis Structure
polarity:
e group arrangement:
shape/molecular geometry:
polarity:
Sketch (with angles):
Sketch (with angles):
Sketch (with angles):