Chapter 12, Problem 12.51QE

(a)

Interpretation Introduction

Interpretation:

Henry’s law constant for ozone has to be calculated in $\text{molal/torr}$.

Concept Introduction:

Henry’s law states that the solubility of the gas at a given temperature is directly proportional to the partial pressure of the gas.  This can be represented in equation form as shown below;

    $\begin{array}{l}C\propto P\\ C=kP\end{array}$

Where,

    $C$ is the concentration of gas.

    $k$ is the proportionality constant.

    $P$ is the partial pressure.

(b)

Interpretation Introduction

Interpretation:

Henry’s law constant will be larger, smaller, or the same for the solution of ozone at $\text{10}\text{°C}$, $\text{1}\text{.00}\text{atm}$ and at $\text{20}\text{°C}$, $\text{1}\text{.00}\text{atm}$ has to be given.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Molal solubility of ozone in water has to be calculated at $\text{0}\text{.500}\text{atm}$ and $\text{0}\text{°C}$.

Concept Introduction:

Refer to part (a).