Chemistry Principles And Practice
Chemistry Principles And Practice
3rd Edition
ISBN: 9781305295803
Author: David Reger; Scott Ball; Daniel Goode
Publisher: Cengage Learning
Question
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Chapter 12, Problem 12.20QE

(a)

Interpretation Introduction

Interpretation:

The concentration of [CO(NH2)2] in mass percentage has to be calculated.

Concept Introduction:

Mass percentage:  The mass percentage gives the number of grams of solute present in 100g of solution.  The formula of mass percentage is,

  Masspercentage=GramsofsoluteGramsofsolution×100%

(a)

Expert Solution
Check Mark

Answer to Problem 12.20QE

The concentration of [CO(NH2)2] in mass percentage is 2.9503%.

Explanation of Solution

Given,

Mass of [CO(NH2)2]    =3.80 g

Mass of water        =125.0g

Mass of solution    =128.8g

The mass percentage of [CO(NH2)2] is given as,

  Masspercentage=GramsofsoluteGramsofsolution×100%Masspercentage=3.80g128.8g×100%Masspercentage=2.9503%

The concentration of [CO(NH2)2] in mass percentage is 2.9503%.

(b)

Interpretation Introduction

Interpretation:

The concentration of [CO(NH2)2] in mole fraction has to be calculated.

Concept Introduction:

Mole fraction:  Mole fraction of a substance in a solution is the number of moles of that substance divided by the total number of moles of all substances present.  The formula is,

  χA=MolesofA (inmol)MolesofA (in mol) +MolesofB (in mol) +MolesofC (in mol) +...χA=MolesofA (inmol)Totalnumberofmolesofcomponents(inmol)

(b)

Expert Solution
Check Mark

Answer to Problem 12.20QE

The concentration of [CO(NH2)2] in mole fraction is 0.0090.

Explanation of Solution

Given,

Mass of [CO(NH2)2]    =3.80 g

Mass of water        =125.0g

Mass of solution    =128.8g

The moles of [CO(NH2)2]=3.80g×1mol60.06g=0.0632moles

The moles of water=125g×1mol18.02g=6.9367moles

The mole fraction of [CO(NH2)2],

  χ[CO(NH2)2]=Molesof[CO(NH2)2] (inmol)Totalnumberofmolesofcomponents(inmol)χ[CO(NH2)2]=0.0632moles0.0632moles+ 6.9367molesχ[CO(NH2)2]=0.0632moles6.9999molesχ[CO(NH2)2]=0.0090

The concentration of [CO(NH2)2] in mole fraction is 0.0090.

(c)

Interpretation Introduction

Interpretation:

The concentration of [CO(NH2)2] in molality has to be calculated.

Concept Introduction:

Molality:  Molality is defined as moles of solute per specified amount of mass of the solvent.  The formula is,

  Molality(m)=Mass ofsolute (in mol)Massofsolvent (in kg)

(c)

Expert Solution
Check Mark

Answer to Problem 12.20QE

The concentration of [CO(NH2)2] in molality is 0.51m.

Explanation of Solution

Given,

Mass of [CO(NH2)2]    =3.80 g

Mass of water        =125.0g=0.125kg

Mass of solution    =128.8g

The moles of [CO(NH2)2]=3.80g×1mol60.06g=0.0632moles

The concentration of [CO(NH2)2] is,

  Molality(m)=Mass ofsolute (in mol)Massofsolvent (in kg)m=0.0632moles0.125kgm=0.5056m0.51m

The concentration of [CO(NH2)2] in molality is 0.51m.

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Chapter 12 Solutions

Chemistry Principles And Practice

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