Explanation Given info: A 5.00 kg object has centre of gravity at ( 0 , 0 ) m , a 3.00 kg object has center of gravity at ( 0 , 4.00 ) m , a 4.00 kg object has center of gravity at ( 3.00 , 0 ) m , the mass of fourth object is 8.00 kg and the centre of gravity for the complete four-object arrangement is ( 0 , 0 ) . Formula to calculate center of gravity is, ( x cm , y cm ) = ( m 1 x 1 + m 2 x 2 + m 3 x 3 + m 4 x 4 m 1 + m 2 + m 3 + m 4 , m 1 y 1 + m 2 y 2 + m 3 y 3 + m 4 y 4 m 1 + m 2 + m 3 + m 4 ) Here, m 1 is the mass of first object. m 2 is the mass of second object. m 3 is the mass of second object. m 4 is the mass of the four object. x 1 is the positions of centre of gravity of the m 1 . x 2 is the positions of centre of gravity of the m 2 . x 3 is the positions of centre of gravity of the m 3 . x 4 is the positions of centre of gravity of the m 4 . y 1 is the position of the centre of gravity of the m 1 . y 2 is the position of the centre of gravity of the m 2 . y 3 is the position of the centre of gravity of the m 3 . y 4 is the position of the centre of gravity of the m 4 . Substitute 5.00 kg for m 1 , 3.00 kg for m 2 , 4.00 kg for m 3 , 8.00 kg for m 4 , 0 m for x 1 , 0 m for x 2 , 3.00 m for x 3 , 0 m for y 1 , 4.00 m for y 2 , 0 m for y 3 and 0 m for x cm and 0 m for y cm in the above equation. ( 0 , 0 ) = ( ( 5

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

Question

Chapter 12, Problem 12.4P

To determine

The position of fourth mass so that center of gravity for the four object arrangement to be at (0,0) .

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Chapter 12, Problem 12.3P

Chapter 12, Problem 12.5P

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Physics for Scientists and Engineers, Technology Update (No access codes included)

Ch. 12 - Consider the object subject to the two forces of...Ch. 12 - Consider the object subject to the three forces in...Ch. 12 - A meterstick of uniform density is hung from a...Ch. 12 - For the three parts of this Quick Quiz, choose...Ch. 12 - The acceleration due to gravity becomes weaker by...Ch. 12 - A rod 7.0 in long is pivoted at a point 2.0 m from...Ch. 12 - Prob. 12.3OQ Ch. 12 - Two forces are acting on an object. Which of the...Ch. 12 - Prob. 12.5OQ Ch. 12 - A 20.0-kg horizontal plank 4.00 in long rests on...

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The position of fourth mass so that center of gravity for the four object arrangement to be at ( 0 , 0 ) .

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The position of fourth mass so that center of gravity for the four object arrangement to be at (0,0) .

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