(a) Interpretation: The peaks of 2 -chloropentane at m / z = 71 and m / z = 70 are to be classified as an even-electron and an odd-electron peak. Concept introduction: In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

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Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

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Answer 2

Question

Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

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Answer 3

Question

Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Expert Solution & Answer

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Answer 4

Question

Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Expert Solution & Answer

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Answer 5

Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 6

Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Answer 7

Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of 2-chloropentane at m/z=71 and m/z=70 are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as (M+1) peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Answer 12

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Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 12 - Prob. 12.1P Ch. 12 - Prob. 12.2P Ch. 12 - Prob. 12.3P Ch. 12 - Prob. 12.4P Ch. 12 - Prob. 12.5P Ch. 12 - Prob. 12.6P Ch. 12 - Prob. 12.7P Ch. 12 - Prob. 12.8P Ch. 12 - Prob. 12.9P Ch. 12 - Prob. 12.10P

Solution Summary: The author explains that in mass spectrometry, an electron is lost to form a molecular ion.

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Chapter 12 Solutions