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Interpretation:
The supersaturated solution needs to be explained. During precipitation hardening, the use of supersaturated solutions needs to be explained. The importance of the formation of a supersaturated solution needs to be explained.
Concept Introduction:
The supersaturated solutions are those types of solution that comprise additionally of the dissolved material than it could be liquified by the solvent under the usualconditions. This can also be referred to as vapor of a compound that has a higher pressure than the vapor pressure of that compound. A solution comprises of a solvent, that is the material which dissolves the solute. In a regular solution, the solvent is usually greater than the solute for it to dissolve. Therefore, the supersaturated solution is dissimilar.
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Chapter 12 Solutions
Essentials Of Materials Science And Engineering
- help on this question about electrical machinery?arrow_forward7. Character AnalysisIf you have downloaded the source code you will find a file named text.txt in the Chapter 08 folder. Write a program that reads the file’s contents and determines the following: The number of uppercase letters in the file The number of lowercase letters in the file The number of digits in the file The number of whitespace characters in the filearrow_forwardA simply supported beam for a building interior with 18 ft span has a cross section of 12 in width and 21 in overall depth. The beam is made with 5 ksi compressive strength concrete and 60 ksi reinforcing steel. The beam supports a uniform service superimposed dead load of 1.6 kip/ft, and a uniform service live load of 80 psf throughout the span. The beams are laterally spaced 20 ft apart c/c. Design this beam and show in a sketch.arrow_forward
- Ternary Phase Diagram+ Material balance One thousand kg/h of a (50-50 wt%) acetone-in-water solution is to be extracted at 25C in a continuous, countercurrent system with pure 1,1,2-trichloroethane to obtain a raffinate containing 10 wt% acetone. Using the following equilibrium data, determine with an equilateral-triangle diagram: a- the minimum flow rate of solvent; b- the number of stages required for a solvent rate equal to 1.5 times minimum, and composition of each streamleaving each stage. c. Repeat the calculation of (a) and (b) if the solvent used has purity 93wt% (4wr% acetone, 3wt% water impurities) acetone water 1,1,2-trichloroethane Raffinate. Weight Extract. Weight 0.6 0.13 0.27 Fraction Acetone Fraction Acetone 0.5 0.04 0.46 0.44 0.56 0.4 0.03 0.57 0.29 0.40 0.3 0.02 0.68 0.12 0.18 0.2 0.015 0.785 0.0 0.0 0.1 0.01 0.89 0.55 0.35 0.1 0.5 0.43 0.07 0.4 0.57 0.03 0.3 0.68 0.02 0.2 0.79 0.01 0.1 0.895 0.005arrow_forwardThe dam presented below is 180 m long (in the direction perpendicular to the plane of the cross-section). For the water elevations given on the drawing: a) Construct the flow net (minimum number of equipotential lines should be 10), b) Calculate the rate of seepage for the entire dam, c) Find the total uplift force on the dam (ignore barriers), and d) Estimate the hydraulic gradient at points A, B, and D. Recommended to use a spreadsheet to include all equations for calculations of potentials.arrow_forwardI need the real handdrawing complete it by adding these : Pneumatic Valves Each linear actuator must be controlled by a directional control valve (DCV) (e.g., 5/2 or 4/2 valve). The bi-directional motor requires a reversible valve to change rotation direction. Pressure Regulators & Air Supply Include two pressure regulators as per the assignment requirement. Show the main compressed air supply line connecting all components. Limit Switches & Safety Features Attach limit switches to each actuator to detect positions. Implement a two-handed push-button safety system to control actuator movement. Connections Between Components Draw air supply lines linking the compressor, valves, and actuators. Clearly label all inputs and outputs for better understanding.arrow_forward
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- A 460 V 25 HP 4 poles connected in Y wound rotor induction motor has the following parameters: R1 = 0.641 ohms, X1 = 1.106 ohms, R2 = 0.332 ohms, X2 = 0.464 ohms and Xm = 26.3 ohms. For this machine calculate the maximum torque, rotation and corresponding slip.arrow_forwardUsing A36 steel select the lightest equal leg single angle member to resist a factored (LRFD) tensile load Pu = 167 kips. The member will be connected through one leg with one line of three 3/4-in Ø bolts spaced at 3 in between centers as shown. The edge distances Leh = Lev = 1.5 in. Use LRFD Method Use U from Table D3.1, Case 8. See attached (D3.1 Case 8, Shear Strength of Bolts, Table 1-7 Dimensions of Angles).arrow_forwardFor the following circuit. What is Vr. Additionally, what is the threshold input voltage VL that will change the output of the comparator from hight ot low.arrow_forward
- MATLAB: An Introduction with ApplicationsEngineeringISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncEssentials Of Materials Science And EngineeringEngineeringISBN:9781337385497Author:WRIGHT, Wendelin J.Publisher:Cengage,Industrial Motor ControlEngineeringISBN:9781133691808Author:Stephen HermanPublisher:Cengage Learning
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