CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Question
Chapter 12, Problem 12.120SP
Interpretation Introduction
Interpretation:
The reason that explains silicon is more brittle than copper should be determined.
Concept introduction:
The ceramic material can be defined as an inorganic, nonmetallic and nonmolecular solid that contains both crystalline materials such as quartz and amorphous material such as glasses.
The ceramic material can be classified as superior to metal because of following properties as follows:
(1) Higher melting point
(2) Stiffer than metal
(3) More resistance towards corrosion and oxidation.
(4) It maintains its strength at higher temperatures
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3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
A chemistry graduate student is studying the rate of this reaction:
2 HI (g) →H2(g) +12(g)
She fills a reaction vessel with HI and measures its concentration as the reaction proceeds:
time
(minutes)
[IH]
0
0.800M
1.0
0.301 M
2.0
0.185 M
3.0
0.134M
4.0
0.105 M
Use this data to answer the following questions.
Write the rate law for this reaction.
rate
= 0
Calculate the value of the rate constant k.
k =
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
Chapter 12 Solutions
CHEMISTRY-TEXT
Ch. 12 - Calcium metal crystallizes in a cubic...Ch. 12 - Polonium metal crystallizes in a simple cubic...Ch. 12 - Polonium metal crystallizes in a simple cubic...Ch. 12 - The density of a sample of metal "as measured to...Ch. 12 - Zinc sulfide crystallizes in the following cubic...Ch. 12 - Prob. 12.6ACh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8ACh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10A
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12ACh. 12 - Prob. 12.13PCh. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Identify each of the following kinds of packingCh. 12 - Prob. 12.19CPCh. 12 - Titanium oxide crystallizes in the following cubic...Ch. 12 - Prob. 12.21CPCh. 12 - Prob. 12.22CPCh. 12 - Prob. 12.23CPCh. 12 - Prob. 12.24CPCh. 12 - Prob. 12.25CPCh. 12 - Prob. 12.26SPCh. 12 - Prob. 12.27SPCh. 12 - Prob. 12.28SPCh. 12 - Prob. 12.29SPCh. 12 - Prob. 12.30SPCh. 12 - Prob. 12.31SPCh. 12 - Diffraction of X rays with =154.2 pm at an angle...Ch. 12 - Diffraction of X rays with =154.2 pm at an angle...Ch. 12 - Which of the four kinds of packing used by metals...Ch. 12 - What is a unit cell? How many atoms are in one...Ch. 12 - Copper crystallizes in a face-centered cubic unit...Ch. 12 - Lead crystallizes in a cubic unit cell with anedge...Ch. 12 - Prob. 12.38SPCh. 12 - Tungsten crystallizes in a body-centered cubic...Ch. 12 - Prob. 12.40SPCh. 12 - Prob. 12.41SPCh. 12 - Titanium metal has a density of and an atomic...Ch. 12 - Calcium metal has a density of 1.55 g/cm3 and...Ch. 12 - The atomic radius of Pb is 175 pm, and the density...Ch. 12 - The density of a sample of metal was measured to...Ch. 12 - If a protein can be induced to crystallize, its...Ch. 12 - The molecular structure of a scorpion toxin, a...Ch. 12 - Iron crystallizes in a body-centered cubic unit...Ch. 12 - Silver metal crystallizes in a face-centered cubic...Ch. 12 - Sodium hydride, NaH, crystallizes in a...Ch. 12 - Cesium chloride crystallizers in a cubic unit cell...Ch. 12 - If the edge length of an NaH unit cell is 488 pm,...Ch. 12 - The edge length of a CsCI unit cell (Problem...Ch. 12 - Silicon carbide, SiC, is a covalent network solid...Ch. 12 - Prob. 12.55SPCh. 12 - Prob. 12.56SPCh. 12 - Prob. 12.57SPCh. 12 - Prob. 12.58SPCh. 12 - Prob. 12.59SPCh. 12 - Prob. 12.60SPCh. 12 - Prob. 12.61SPCh. 12 - Prob. 12.62SPCh. 12 - Prob. 12.63SPCh. 12 - Prob. 12.64SPCh. 12 - Prob. 12.65SPCh. 12 - Prob. 12.66SPCh. 12 - Prob. 12.67SPCh. 12 - Prob. 12.68SPCh. 12 - Prob. 12.69SPCh. 12 - Prob. 12.70SPCh. 12 - Prob. 12.71SPCh. 12 - Prob. 12.72SPCh. 12 - Prob. 12.73SPCh. 12 - Prob. 12.74SPCh. 12 - Prob. 12.75SPCh. 12 - Prob. 12.76SPCh. 12 - Prob. 12.77SPCh. 12 - Prob. 12.78SPCh. 12 - Prob. 12.79SPCh. 12 - Prob. 12.80SPCh. 12 - Prob. 12.81SPCh. 12 - Prob. 12.82SPCh. 12 - Prob. 12.83SPCh. 12 - Prob. 12.84SPCh. 12 - Prob. 12.85SPCh. 12 - Prob. 12.86SPCh. 12 - Prob. 12.87SPCh. 12 - Prob. 12.88SPCh. 12 - Prob. 12.89SPCh. 12 - Prob. 12.90SPCh. 12 - Prob. 12.91SPCh. 12 - Prob. 12.92SPCh. 12 - Prob. 12.93SPCh. 12 - Prob. 12.94SPCh. 12 - Prob. 12.95SPCh. 12 - Prob. 12.96SPCh. 12 - Prob. 12.97SPCh. 12 - Prob. 12.98SPCh. 12 - Prob. 12.99SPCh. 12 - Prob. 12.100SPCh. 12 - Prob. 12.101SPCh. 12 - A photovoltaic cell contains a p-n junction that...Ch. 12 - Prob. 12.103SPCh. 12 - Prob. 12.104SPCh. 12 - Prob. 12.105SPCh. 12 - Prob. 12.106SPCh. 12 - Prob. 12.107SPCh. 12 - Prob. 12.108SPCh. 12 - Prob. 12.109SPCh. 12 - Prob. 12.110SPCh. 12 - Prob. 12.111SPCh. 12 - Prob. 12.112SPCh. 12 - Prob. 12.113SPCh. 12 - Prob. 12.114SPCh. 12 - Prob. 12.115SPCh. 12 - Prob. 12.116SPCh. 12 - Prob. 12.117SPCh. 12 - Prob. 12.118SPCh. 12 - Prob. 12.119SPCh. 12 - Prob. 12.120SPCh. 12 - Prob. 12.121SPCh. 12 - Prob. 12.122SPCh. 12 - Prob. 12.123SPCh. 12 - Prob. 12.124SPCh. 12 - Prob. 12.125SPCh. 12 - Prob. 12.126SPCh. 12 - Prob. 12.127SPCh. 12 - Prob. 12.128SPCh. 12 - Prob. 12.129SPCh. 12 - Prob. 12.130SPCh. 12 - Prob. 12.131SPCh. 12 - Prob. 12.132SPCh. 12 - Prob. 12.133SPCh. 12 - Prob. 12.134MPCh. 12 - Prob. 12.135MPCh. 12 - Prob. 12.136MPCh. 12 - Prob. 12.137MPCh. 12 - Assume that 1588 g of an alkali metal undergoes...Ch. 12 - Prob. 12.139MPCh. 12 - Prob. 12.140MPCh. 12 - Prob. 12.141MPCh. 12 - Prob. 12.142MPCh. 12 - Prob. 12.143MPCh. 12 - Prob. 12.144MP
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