Atoms with electron configurations [ Kr ] 5 s 2 4 d 10 5 p 6 , [ Kr ] 5 s 2 4 d 10 5 p 1 , [ Kr ] 5 s 2 4 d 10 5 p 3 should be identified and should be arranged based on least to greatest size. Concept introduction: As one moves from top to bottom the shells expands and size increases, while it decreases as one moves along the period because of gradual increases in effective nuclear charge. This in turn increases influence of nucleus on valence electron and shrinks the radius along the horizontal row.
Atoms with electron configurations [ Kr ] 5 s 2 4 d 10 5 p 6 , [ Kr ] 5 s 2 4 d 10 5 p 1 , [ Kr ] 5 s 2 4 d 10 5 p 3 should be identified and should be arranged based on least to greatest size. Concept introduction: As one moves from top to bottom the shells expands and size increases, while it decreases as one moves along the period because of gradual increases in effective nuclear charge. This in turn increases influence of nucleus on valence electron and shrinks the radius along the horizontal row.
Solution Summary: The author explains that as one moves from top to bottom the shells expand and size increases, while it decreases due to gradual increases in effective nuclear charge.
Interpretation: Atoms with electron configurations [Kr]5s24d105p6 , [Kr]5s24d105p1 , [Kr]5s24d105p3 should be identified and should be arranged based on least to greatest size.
Concept introduction:As one moves from top to bottom the shells expands and size increases, while it decreases as one moves along the period because of gradual increases in effective nuclear charge. This in turn increases influence of nucleus on valence electron and shrinks the radius along the horizontal row.
(b)
Interpretation Introduction
Interpretation:Atoms with configurations [Ne]3s23p5 , [Ar]4s23d104p3 , [Kr]5s24d105p3 should be identified and should be arranged based on least to ionization energy.
Concept introduction: In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy.
The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons.
The decomposition of dinitrogen pentoxide according to the equation:
50°C
2 N2O5(g)
4 NO2(g) + O2(g)
follows first-order kinetics with a rate constant of 0.0065 s-1. If the initial
concentration of N2O5 is 0.275 M, determine:
the final concentration of N2O5 after 180 seconds.
...
Don't used hand raiting
CS2(g) →CS(g) + S(g)
The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹.
S
What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell