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(a)
Interpretation:Atoms
Concept introduction:In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy.
The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons.
An inverse trend between atomic radius and ionization energy is found because As one moves from top to bottom the shells expand and size increases; this triggers outermost electron to remain far from any influence of nucleus. Therefore more easier is removal of electron.
(b)
Interpretation:Atoms
Concept introduction:An inverse trend between atomic radius and ionization energy is found because As one moves from top to bottom the shells expand and size increases; this triggers outermost electron to remain far from any influence of nucleus. Therefore more easier is removal of electron.
(c)
Interpretation:Atoms
Concept introduction:An inverse trend between atomic radius and ionization energy is found because As one moves from top to bottom the shells expand and size increases; this triggers outermost electron to remain far from any influence of nucleus. Therefore more easier is removal of electron.
(d)
Interpretation:Atoms
Concept introduction:An inverse trend between atomic radius and ionization energy is found because As one moves from top to bottom the shells expand and size increases; this triggers outermost electron to remain far from any influence of nucleus. Therefore more easier is removal of electron.
(e)
Interpretation:Atom
Concept introduction:An inverse trend between atomic radius and ionization energy is found because As one moves from top to bottom the shells expand and size increases; this triggers outermost electron to remain far from any influence of nucleus. Therefore more easier is removal of electron.
(f)
Interpretation:Atom
Concept introduction:An inverse trend between atomic radius and ionization energy is found because As one moves from top to bottom the shells expand and size increases; this triggers outermost electron to remain far from any influence of nucleus. Therefore more easier is removal of electron.
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Chapter 12 Solutions
EBK CHEMICAL PRINCIPLES
- X Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forward
- Nonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forward
- Predict and draw the product of the following organic reaction:arrow_forwardNonearrow_forwardRedraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forward
- Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
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