Trend in electron affinity values from Al to Cl as − 44 kJ/mol , − 120 kJ/mol , − 74 kJ/mol , − 200.4 kJ/mol and − 348.7 kJ/mol should be rationalized. Concept introduction: In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy. The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons. Reverse of ionization process may result in a gain of one or more electron as exhibited by groups 16 and 17 to attain noble core configuration. These groups have 6 and seven valence electrons and hence favorably accept 2 and 1 electron respectively. This behavior is termed as electron affinity.
Trend in electron affinity values from Al to Cl as − 44 kJ/mol , − 120 kJ/mol , − 74 kJ/mol , − 200.4 kJ/mol and − 348.7 kJ/mol should be rationalized. Concept introduction: In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy. The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons. Reverse of ionization process may result in a gain of one or more electron as exhibited by groups 16 and 17 to attain noble core configuration. These groups have 6 and seven valence electrons and hence favorably accept 2 and 1 electron respectively. This behavior is termed as electron affinity.
Solution Summary: The author explains that the energy imparted to convert an atom to gaseous species is ionization energy, which is determined by how effectively valence electron is held by the nucleus.
Study of body parts and their functions. In this combined field of study, anatomy refers to studying the body structure of organisms, whereas physiology refers to their function.
Chapter 12, Problem 118E
Interpretation Introduction
Interpretation:Trend in electron affinity values from Al to Cl as −44 kJ/mol , −120 kJ/mol , −74 kJ/mol , −200.4 kJ/mol and −348.7 kJ/mol should be rationalized.
Concept introduction:In order to remove the electron situated in outermost shell certain minimum energy must be imparted to convert an atom to gaseous species. The energy thus imparted represents ionization energy.
The magnitude of ionization energy is determined by how effectively valence electron is held by the nucleus. If the outermost shell has, for instance, one or two electrons that require very minimum ionization energy as they can attain the noble gas configuration upon loss of those electrons.
Reverse of ionization process may result in a gain of one or more electron as exhibited by groups 16 and 17 to attain noble core configuration. These groups have 6 and seven valence electrons and hence favorably accept 2 and 1 electron respectively. This behavior is termed as electron affinity.
3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
A chemistry graduate student is studying the rate of this reaction:
2 HI (g) →H2(g) +12(g)
She fills a reaction vessel with HI and measures its concentration as the reaction proceeds:
time
(minutes)
[IH]
0
0.800M
1.0
0.301 M
2.0
0.185 M
3.0
0.134M
4.0
0.105 M
Use this data to answer the following questions.
Write the rate law for this reaction.
rate
= 0
Calculate the value of the rate constant k.
k =
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
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