Chapter 11.6, Problem 37HP

(a)

To determine

To state: The perimeter and area of the new parallelogram.

Answer to Problem 37HP

Perimeter = 44 in

Area ${\text{=120 in}}^2$

Explanation of Solution

Given: The given parallelogram is

  

If two parallelogram have same area both are on same base and same parallel line.

  

The dimension of new parallelogram 12 in by 10 in

The perimeter of parallelogram, $PTSU=12+10+12+10=44\text{ in}$

The area of parallelogram, $PTSU=12\times 10=120{\text{ in}}^2$

(b)

To determine

To state: The parallelogram with same perimeter and different area.

Answer to Problem 37HP

Perimeter = 48 in

Area ${\text{=140 in}}^2$

Explanation of Solution

Given: The given parallelogram is

  

First draw a new parallelogram with same perimeter. The perimeter of QRST is 48 in.

  

The dimension of new parallelogram 14 in by 10 in

The perimeter of parallelogram, $PTSU=14+10+14+10=48\text{ in}$

The area of parallelogram, $PTSU=14\times 10=140{\text{ in}}^2$