Chapter 11.1, Problem 40STP

To determine

To Find: The measure of ‘x’.

Answer to Problem 40STP

  $x^{°}={148}^{°}$

Explanation of Solution

Given information:

Concept and Formula Used:

The sum of supplementary angles is ${180}^{°}$

Calculation:

The given figure is

From the figure the angle with measure

  $x^{°}\&{32}^{°}$ are supplementary to each other. As the sum of supplementary angles is ${180}^{°}$

Therefore

  $\begin{array}{l}{x}^{°}+{32}^{°}={180}^{°}\\ x^{°}={180}^{°}-{32}^{°}\\ x^{°}={148}^{°}\end{array}$

Conclusion:

  $x^{°}={148}^{°}$