Chapter 11.3, Problem 26SR

a.

To determine

To calculate: The distance from the right metal plate connector to the center web.

Answer to Problem 26SR

The distance from the right metal plate connector to the center web is 16 ft .

Explanation of Solution

Given:

  $\Delta TRU\cong \Delta SRU$ , $TS=32ft$

Since, $\Delta TRU$ and $\Delta SRU$ are congruent to each other, then their corresponding sides are equal.

Thus, $TU=SU$

Now,

  $\begin{array}{l}TS=32ft\\ \Rightarrow TU+US=32ft\\ \Rightarrow TU+SU=32ft\\ \Rightarrow SU+SU=32ft[\because TU=SU]\\ \Rightarrow 2SU=32ft\\ \Rightarrow SU=\frac{32}{2}ft\\ \Rightarrow SU=16ft\end{array}$

Conclusion:

Thus SU ,that is, the distance from the right metal plate connector to the center web is 16ft

b.

To determine

To calculate:The measure of the angle formed by the top left chord and the bottom chord.

Answer to Problem 26SR

The measure of the angle formed by the top left chord and the bottom chord is $30°$ .

Explanation of Solution

Given:

  $\Delta TRU\cong \Delta SRU$ and $\angle RSU=30°$

Calculation:

Since, $\Delta TRU$ and $\Delta SRU$ are congruent to each other, then their corresponding angles are equal.

Thus, $\angle RSU=\angle RTU$

Since, $\angle RSU=30°$ then, $\angle RTU=30°$

Conclusion:

Thus, $\angle RTU$ , that is, the measure of the angle formed by the top left chord and the bottom chord is $30°$ .