Chapter 11.6, Problem 24PPS

To determine

To Find: The area of the given figure.

Answer to Problem 24PPS

  $A=121\text{ sq}\text{.cm}$

Explanation of Solution

Given information:

The given figure is

Concept and Formula Used:

Area of triangle $A=\frac{1}{2}bh$ & Area of square $A={\left(side\right)}^2$

Calculation:

The given figure is combination of triangle and square.

To find the area of the figure add the area of triangle and square.

The side of the square is $s=10cm$ and the base of triangle is equal to side of square i.e. $b=10cm$ and height of triangle is $h=4.2cm$

Area of figure is sum of area of square and triangle.

  $\begin{array}{l}\text{Area}=\text{Area of triangle}+\text{Area of square}\\ A=\frac{1}{2}bh+{\left(s\right)}^2\\ \text{where b}=10c\text{m,}h=4.2cm\&s=10cm\\ A=\frac{1}{2}\left(10\right)\left(4.2\right)+{\left(10\right)}^2\\ A=21+100\\ A=121\text{ sq}\text{.cm}\end{array}$

Conclusion:

  $A=121\text{ sq}\text{.cm}$