Decode the message 001111 100100 001100 . Hamming Distance: The hamming distance between two bit patterns is the number of bits in which the patterns differ. An error correcting code is, Symbol Value represented A 000000 B 001111 C 010011 D 011100 E 100110 F 101001 G 110101 H 111010 Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

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Answer 1

Expert Solution & Answer

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

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1. Create a Person.java file. Implement the public Person and Student classes in Person.java, including all the variables and methods in the UMLS. Person -name: String -street: String -city: String +Person(String name, String, street, String, city) +getName(): String +setName(String name): void +getStreet(): String +setStreet(String street): void +getCity(): String +setCity(String City): void +toString(): String Student -Id: int +Person(String name, String, street, String, city, int Id) +getId(): int +setId(int Id): void +toString(): String 2. Create a StudentTest.java file. Implement a public StudentTest class with a main method. In the main method, create one student object and print the object using System.out.println(). Your printing result must follow the example output: name: Mike, street: Morris Ave, city: Union, Id: 1000 Hint: You need to modify the toString methods in the Student class and Person class!

1) Apply the Paint Blue algorithm discussed in class to the following Finite Automata. a a a b b a COIS-3050H-R-W01-2025WI-COMB Formal Languages & Automata a b Show the status of the Finite Automata at the conclusion of the Paint Blue Algorithm (mark the visited states with an X and only include edges that have not been followed). 2) Use the pumping lemma to prove the following language is nonregular: L= {ab} = {abbb, aabbbbbb, aaabbbbbbbbb, ...}

3) Find CFGs that for these regular languages over the alphabet Σ= {a, b}. Draw a Finite Automata e CFG. 1 COIS-3050H-R-W01-2025WI-COMB Formal anguages & Automata Is that contain the substring aba. (b) The language of all words that have an odd number letters and contains the string bb. (c) The language of all words that begin with the substring ba and contains an odd number of letters. 4) Convert the following FA into a PDA. a a S± b a a Ν Ꮓ

Answer 2

Expert Solution & Answer

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

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Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

Answer 8

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

Answer 9

Chapter 1.10, Problem 5QE

a.

Explanation of Solution

Decode the message 001111 100100 001100.

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G 110101
H 111010

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern

Answer 10

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

Answer 11

b.

Explanation of Solution

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

Answer 12

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

Answer 13

c.

Explanation of Solution

Decode the message 011010 110110 100000 011100.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011010 matches with H of table 1 because 011010 and 111010 differ by one hamming distance.

The pattern 110110 matches with E of table 1 because 110110 and 100110 differ only by one hamming distance

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

Ch. 1.1 - What input bit patterns will cause the following...Ch. 1.1 - In the text, we claimed that placing a 1 on the...Ch. 1.1 - Assuming that both inputs to the flip-flop in...Ch. 1.1 - a. If the output of an AND gate is passed through...Ch. 1.1 - Prob. 5QE Ch. 1.1 - Prob. 6QE Ch. 1.2 - If the memory cell whose address is 5 contains the...Ch. 1.2 - Prob. 2QE Ch. 1.2 - How many bits would be in the memory of a computer...Ch. 1.3 - Prob. 1QE

Symbol	Value represented
A	000000
B	001111
C	010011
D	011100
E	100110
F	101001
G	110101
H	111010

Explanation of Solution

Explanation of Solution

Decode the message 010001 000000 001011. Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern. The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance

Explanation of Solution

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Chapter 1 Solutions

Decode the message 010001 000000 001011.

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010001 matches with C of table 1 because 010001 and 010011 differ by one hamming distance