Chapter 1, Problem 45CRP

Explanation of Solution

The length of the string being used to represent binary is changed from 4 bits to 6 bits.

The change that would be made in the value of the largest integer is:

• Convert the $4\text{bits}$ binary number that is $1111$ into integer.

  $1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=15$

  The value of largest integer is $15$.

• Convert the $6\text{bits}$ binary number that is $111111$ into integer.

  $1\times 2^5+1\times 2^4+1\times 2^3+1\times 2^2+1\times 2^1+1\times 2^0=63$

  The largest integer is $63$ when $6\text{bits}$ are only used.

• The two’s complement having the positive value using $4\text{bits}$ is $0111$