Decode the message 111010 110110 : Hamming Distance: The hamming distance between two bit patterns is the number of bits in which the patterns differ. An error correcting code is, Symbol Value represented A 000000 B 001111 C 010011 D 011100 E 100110 F 101001 G

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Answer 1

Expert Solution & Answer

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

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For the three code words:C1= [110110011], C2= [100101100]andC3=[111100101]. Determine the possible error detection and the possible error .correction

Decode the following ASCII coded message:1001000 1100101 1101100 1101100 1101111 01011100100000 1001000 1101111 1110111 0100000 11000011110010 1100101 0100000 1111001 1101111 11101010111111

6. Decode the following ASCII message. 01001001 00100000 01101000 01101111 01110000 01100101 00100000 01110100 01101000 01100001 01110100 00100000 01111001 01101111 01110101 00100000 01100001 01110010 01100101 00100000 01100010 01100101 01101001 | 01101110 01100111 O0100000 01110110 01100101 01110010 01111001 00100000 01100011 01100001 01110010 01100101 O1100110 01110101 01101100 00100001

Answer 2

Expert Solution & Answer

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

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Answer 3

Expert Solution & Answer

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

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Answer 4

Expert Solution & Answer

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

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Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

Answer 8

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

Answer 9

Chapter 1, Problem 54CRP

a.

Explanation of Solution

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

Answer 10

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

Answer 11

b.

Explanation of Solution

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

Answer 12

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

Answer 13

c.

Explanation of Solution

Decode the message 011101 000110 000000 010100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 011101 matches with D of table 1 because 011101 and 011100 differ by one hamming distance.

The pattern 000110 matches with E of table 1 because 000110 and 100110 differ only by one hamming distance

Answer 14

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

Answer 15

d.

Explanation of Solution

Decode the message 010010 001000 001110 101111 000000 110111 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010010 matches with C of table 1 because 010010 and 010011 differ by one hamming distance.

The pattern 001000 matches with A of table 1 because 001000 and 000000 differ only by one hamming distance.

The pattern 001110 matches with B of table 1 because 001110 and 001111 differ only by zero hamming distance.

The pattern 101111 matches with B of table 1 because 101111 and 001111 differ only by one hamming distance

Answer 16

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

Answer 17

e.

Explanation of Solution

Decode the message 010011 000000 101001 100110:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 010011 matches with C of table 1 because 010011 and 010011 differ by zero hamming distance.

The pattern 000000 matches with A of table 1 because 000000 and 000000 differ only by zero hamming distance

Answer 18

Expert Solution & Answer

Answer 19

Expert Solution & Answer

Answer 20

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Answer 21

Ch. 1.1 - What input bit patterns will cause the following...Ch. 1.1 - In the text, we claimed that placing a 1 on the...Ch. 1.1 - Assuming that both inputs to the flip-flop in...Ch. 1.1 - a. If the output of an AND gate is passed through...Ch. 1.1 - Prob. 5QE Ch. 1.1 - Prob. 6QE Ch. 1.2 - If the memory cell whose address is 5 contains the...Ch. 1.2 - Prob. 2QE Ch. 1.2 - How many bits would be in the memory of a computer...Ch. 1.3 - Prob. 1QE

Symbol	Value represented
A	000000
B	001111
C	010011
D	011100
E	100110
F	101001
G

Decode the message 111010 110110 : Hamming Distance: The hamming distance between two bit patterns is the number of bits in which the patterns differ. An error correcting code is, Symbol Value represented A 000000 B 001111 C 010011 D 011100 E 100110 F 101001 G

Explanation of Solution

Decode the message 111010 110110: Hamming Distance: The hamming distance between two bit patterns is the number of bits in which the patterns differ. An error correcting code is, SymbolValue representedA000000B001111C010011D011100E100110F101001G

Explanation of Solution

Decode the message 101000 100110 001100: Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern. The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance

Explanation of Solution

Explanation of Solution

Explanation of Solution

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Chapter 1 Solutions

Decode the message 111010 110110:

Hamming Distance:

The hamming distance between two bit patterns is the number of bits in which the patterns differ.

An error correcting code is,

Symbol Value represented
A 000000
B 001111
C 010011
D 011100
E 100110
F 101001
G

Decode the message 101000 100110 001100:

Compare each pattern with the patterns in the code of table 1 until that pattern is found which is within a distance of one from the received pattern.

The pattern 101000 matches with F of table 1 because 101000 and 101001 differ by one hamming distance