EBK ESSENTIALS OF MIS
12th Edition
ISBN: 8220101459305
Author: LAUDON
Publisher: PEARSON
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Chapter 11, Problem 4RQ
Explanation of Solution
Knowledge management:
Knowledge management is a set of process evolved in an organization in order to create, collect, retain, maintain, transfer, and distribute the firm’s knowledge.
Business value of knowledge management:
- Organization can review the process undergoing in an environment and to learn things and adopt the cultivated knowledge into its business processes.
- This adoption of new knowledge from the other environment enables to business to work efficiently and efficiently.
Types of knowledge management system
There are there types of knowledge management system. They are:
- Enterprise-wide knowledge management system
- Knowledge work systems
- Intelligent techniques
Enterprise-wide knowledge management system and their value to business:
It is used to gather, store, retrieve, distribute and project the digital content and knowledge. It is capable of searching the information which stored in the structured and unstructured data. It helps to business to face new challenges, inventing new methodologies and functionalities. It helps the firm to enhance the better decision making skills.
Knowledge work systems and their value to business:
It is a specialized system build for engineers, scientists and other knowledge workers. The workers are charged with the creation and developing the new knowledge. The managers can easily identify the experts in the firms and can allot the suited operations thus enabling the business to process the operations quickly.
Intelligent techniques:
Intelligent techniques apply the knowledge for making decisions and knowledge domains. Intelligent techniques include fuzzy logic, genetic
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(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Output:
Exercise 1:====================Go Kean! Have a great semester!
Go Kean!
Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!
(OnlineGDB)
1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
What is the output of the program? Please explain why.
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