Concept explainers
Explanation of Solution
Structure:
In C++, the structure is a user-defined data type, which contains different type of elements with different lengths.
- The size of the structure is calculated by the total number of elements which is declared in a structure.
Structure pointer operator (->):
The structure pointer operator (->) can be used with a structure pointer variable to access the members of a structure; this operator does automatically dereferences its left structure pointer.
- It can be referred as an alternative for indirection operator (*).
Example:
The following example is used to declare a function named “getValues()” and then to access the structure members using structure pointer operator (->):
//Include required header files
#include <iostream>
using namespace std;
//Declare a structure
struct Values
{
//Declare the member variables
string name;
int age;
//D...
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Starting Out with C++ from Control Structures to Objects (9th Edition)
- typedef _people { int age; char name[ 32 ] ; } People_T ; People_T data [ 3 ]; Using string lib function, Assign 30 and Cathy to the first cell, Assign 40 and John to the second cell and Assign 50 and Tom to the third cell People_T *ptr ; Declare a pointer pointing to the structure data and print the age and name using the pointer. your output can be : 30 Cathy 40 John 50 Tomarrow_forwardFill-in-the-Blank The __________ operator is used to access structure members.arrow_forward#include #include #include "Product.h" using namespace std; int main() { vector productList; Product currProduct; int currPrice; string currName; unsigned int i; Product resultProduct; cin>> currPrice; while (currPrice > 0) { } cin>> currPrice; main.cpp cin>> currName; currProduct.SetPriceAndName (currPrice, currName); productList.push_back(currProduct); resultProduct = productList.at (0); for (i = 0; i < productList.size(); ++i) { Type the program's output Product.h 1 CSE Scanned Product.cpp if (productList.at (i).GetPrice () < resultProduct.GetPrice ()) { resultProduct = productList.at(i); } AM cout << "$" << resultProduct.GetPrice() << " " << resultProduct. GetName() << endl; return 0; Input 10 Cheese 6 Foil 7 Socks -1 Outputarrow_forward
- /* Movie List Example --Showing how to use vectors and structures */ #include <iostream> #include <iomanip> #include <string> #include <vector> using namespace std; // define a struct for a Movie object struct Movie // It is common for the struct name to be capitalized { string title = ""; // First member of structure - and initialized int year = 0; // Second member of structure - and initialized }; int main() { cout << "The Movie List program\n\n" << "Enter a movie...\n\n"; // get vector of Movie objects vector<Movie> movie_list; char another = 'y'; while (tolower(another) == 'y') { Movie movie; // make temporary new (initialized) Movie object cout << "Title: "; getline(cin, movie.title); cout << "Year: "; cin >> movie.year; movie_list.push_back(movie);…arrow_forward/* Movie List Example --Showing how to use vectors and structures */ #include <iostream> #include <iomanip> #include <string> #include <vector> using namespace std; // define a struct for a Movie object struct Movie // It is common for the struct name to be capitalized { string title = ""; // First member of structure - and initialized int year = 0; // Second member of structure - and initialized }; int main() { cout << "The Movie List program\n\n" << "Enter a movie...\n\n"; // get vector of Movie objects vector<Movie> movie_list; char another = 'y'; while (tolower(another) == 'y') { Movie movie; // make temporary new (initialized) Movie object cout << "Title: "; getline(cin, movie.title); cout << "Year: "; cin >> movie.year; movie_list.push_back(movie);…arrow_forwardstruct Struct {int a[20], double x}; int main() { Struct s1; return 0}; To initialize the elements of structure, following instrunction is the correct option: Struct.a[0] = 50; Struct.x = 5.0; Struct.a = {10, 20, 30, 40}; O All of Above O None of Abovearrow_forward
- #ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…arrow_forwardIn C languagearrow_forward#include <iostream>#include <string>#include <iomanip>using namespace std;// structurestruct Hat{string brand;string color;float price;};// Customer structurestruct Customer{string fullName ;int age ;Hat hat; // Hat structure (nested in Customer)};int main(){// declare 5 variables of CustomerCustomer customer_1,customer_2,customer_3,customer_4,customer_5;cout<<"Welcome to Hats For U!\n";cout<<"Customer 1\n";cout<<"Enter customer's Full Name: ";getline(cin,customer_1.fullName);cout<<"Enter customer's age: ";cin>>customer_1.age;cout<<"Enter the brand of hat: ";cin>>customer_1.hat.brand;cout<<"Enter the hat color: ";cin>>customer_1.hat.color;cout<<"Enter the hat price(RM): ";cin>>customer_1.hat.price; cout<<"Hat 2\n";cout<<"Enter customer's Full Name: ";getline(cin,customer_2.fullName);getline(cin,customer_2.fullName);cout<<"Enter customer's age:…arrow_forward
- #include <iostream> #include<string.h> //user-defined functions question! using namespace std; struct Books { char title[50]; char author[50]; char subject[100]; int book_id; }; int main() { double array1[5]= {13.768,4.0,88.7689,9.12,}; struct Books Book1; strcpy( Book1.title, "C++ Programming"); strcpy( Book1.author, "D.S Malik"); strcpy( Book1.subject, "C++ basics"); Book1.book_id = 6495407; ////Block#1////// int x=4; for (x; x>=0; x--){ cout<<array1[x]<<endl; //////////////////////////////// } cout<<"///////////////////////"<<endl; ////end of Block#1////// ////Block#2////// int sum=0, i=0; for (i; i<5; i++){ cout<<static_cast<int>(array1[i])<<" "; sum= sum+array1[i]; cout<<sum<<endl; } cout<< "final value of sum="<<" "<<sum<<endl; cout<< "the average value ="<<" " <<sum/5 <<endl; cout<<"//////////////////////"<<endl; //arrow_forward#include <iostream> #include<string.h> //user-defined functions question! using namespace std; struct Books { char title[50]; char author[50]; char subject[100]; int book_id; }; int main() { double array1[5]= {13.768,4.0,88.7689,9.12,}; struct Books Book1; strcpy( Book1.title, "C++ Programming"); strcpy( Book1.author, "D.S Malik"); strcpy( Book1.subject, "C++ basics"); Book1.book_id = 6495407; ////Block#1////// int x=4; for (x; x>=0; x--){ cout<<array1[x]<<endl; //////////////////////////////// } cout<<"///////////////////////"<<endl; ////end of Block#1////// ////Block#2////// int sum=0, i=0; for (i; i<5; i++){ cout<<static_cast<int>(array1[i])<<" "; sum= sum+array1[i]; cout<<sum<<endl; } cout<< "final value of sum="<<" "<<sum<<endl; cout<< "the average value ="<<" " <<sum/5 <<endl; cout<<"//////////////////////"<<endl; //arrow_forwardDeclare a student structure that contains : Student's first and last nameStudent IDCreate the following functions: getStudentInfo(void) Declares a single student, uses printf()/scanf() to get inputReturns the single student backprintStudentInfo(student_t *st_ptr) Takes the pointer to a student (to avoid making a copy)Prints out all of the student informationDeclare an array of five studentsUsing a for loop and getStudentInfo() function, get input of all the studentsUsing a for loop and printStudentInfo() function, print all the output of all students.arrow_forward
- C++ for Engineers and ScientistsComputer ScienceISBN:9781133187844Author:Bronson, Gary J.Publisher:Course Technology PtrEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT