Inquiry into Physics
8th Edition
ISBN: 9781337515863
Author: Ostdiek
Publisher: Cengage
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11, Problem 1MIO
To determine
To Describe: The half-life of the radioactive decay process and its applications.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Show what is meant by the radioactive half-life of a radionuclide, using a suitable sketch graph. Mark two half-lives on your graph. Also use your graph to show the relationship of the halflife with τ, the decay constant, or characteristic decay time and τ−1, the decay rate.
Demonstrate your nuclear reaction balancing skills by answering the following three
scenarios.
You will fill the first nine blanks with either an integer numeral (1-3 digits), or the
chemical symbol for an element (1-2 letters). For example, Curium has the chemical
symbol Cm, and its most stable isotope has mass number A=247 and atomic number
Z-96. (These are not answers to this question.)
a) Identify the unknown daughter nucleus (?) in the following reaction:
1
¹235U + ¼n → ¹3¹1 + (?) + 3 (√n)
92
53
Enter the mass number A =
Enter the atomic number Z =
Enter the chemical symbol:
A
N
Consider an initial amount of 708g of radioactive material with half-life h=3.2hdays.
Use a spreadsheet to record the initial amount (at day 0) and to calculate the amounts left at 1day intervals, up to day 10 included.
What is the average amount of material over the time interval from day 0 to day 10? Round your answer to the nearest integer:
Chapter 11 Solutions
Inquiry into Physics
Ch. 11 - Prob. 1MACh. 11 - Prob. 1PIPCh. 11 - Prob. 2PIPCh. 11 - Prob. 1MIOCh. 11 - Prob. 1QCh. 11 - Prob. 2QCh. 11 - Prob. 3QCh. 11 - Prob. 4QCh. 11 - Prob. 5QCh. 11 - Prob. 6Q
Ch. 11 - Prob. 7QCh. 11 - Prob. 8QCh. 11 - Prob. 9QCh. 11 - Prob. 10QCh. 11 - Prob. 11QCh. 11 - Prob. 12QCh. 11 - Prob. 13QCh. 11 - Prob. 14QCh. 11 - Prob. 15QCh. 11 - Prob. 16QCh. 11 - Prob. 17QCh. 11 - Prob. 18QCh. 11 - Prob. 19QCh. 11 - Prob. 20QCh. 11 - Prob. 21QCh. 11 - Prob. 22QCh. 11 - Prob. 23QCh. 11 - Prob. 24QCh. 11 - Prob. 25QCh. 11 - Prob. 26QCh. 11 - Prob. 27QCh. 11 - Prob. 28QCh. 11 - Prob. 29QCh. 11 - Prob. 30QCh. 11 - Prob. 31QCh. 11 - Prob. 32QCh. 11 - Prob. 33QCh. 11 - Determine the nuclear composition (number of...Ch. 11 - The isotope helium-6 undergoes beta decay. Write...Ch. 11 - Prob. 3PCh. 11 - A nucleus of oxygen-15 undergoes electron capture....Ch. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - Prob. 8PCh. 11 - Prob. 9PCh. 11 - Prob. 10PCh. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - . A Geiger counter registers a count rate of 4,000...Ch. 11 - Prob. 14PCh. 11 - Prob. 15PCh. 11 - Prob. 16PCh. 11 - Prob. 17PCh. 11 - Prob. 18PCh. 11 - Prob. 19PCh. 11 - Prob. 20PCh. 11 - Prob. 21PCh. 11 - Prob. 22PCh. 11 - Prob. 1CCh. 11 - Prob. 2CCh. 11 - Prob. 3CCh. 11 - Prob. 4CCh. 11 - Prob. 5CCh. 11 - Prob. 6CCh. 11 - Prob. 7C
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Enter the correct nuclide symbol in each open tan rectangle in Figure P43.25, which shows the sequences of decays in the natural radioactive series starting with the long-lived isotope uranium-235 and ending with the stable nucleus lead-207. Figure P43.25arrow_forwardIf a 1.50cmthick piece of lead can absorb 90.0% of the rays from a radioactive source, how many centimeters of lead are needed to absorb all but 0.100% of the rays?arrow_forwardIf a 1.50-cm-thick piece of lead can absorb 90.0% of the rays from a radioactive source, how many centimeters of lead are needed to absorb all but 0.100% of the rays?arrow_forward
- Suppose you have a pure radioactive material with a half-life of T1/2. You begin with N0 undecayed nuclei of the material at t = 0. At t=12T1/2, how many of the nuclei have decayed? (a) 14N0 (b) 12N0(C) 34N0 (d) 0.707N0 (e) 0.293N0arrow_forwardThe atomic weight of cadmium is 112.41, and its density is 8.65 g/cm3. Using Figure 14.3, estimate the attenuation distance of a thermal neutron beam in cadmium. (The attenuation distance is the distance traveled after which the intensity of the beam is reduced to 1/e of its initial value, where e is the base of the natural logarithms.)arrow_forwardThe following explanation of a fission reactor contains many errors. Please correct as many as you can find. You may copy the whole text out while correcting the errors; in that case please underline what you have changed. You may prefer to use conventional instructions to printers, of the form, para 1 line 1 for ”harnessing” read ”exploiting”, which would cause thetexttoread”. . . byexploitingtheenergy. . . ” A nuclear fission reactor fuelled by uranium operates by harnessing the energy released during the fusing (fission) of uranium atoms into three or four lighter nuclei with less bind- ing energy. Uranium-238 (U-238) is the fissile isotope used. Fission is triggered when the U238 is bombarded by neutrinos, which are absorbed by the orbiting electrons. When a U-235 nucleus undergoes fission, it releases several neutrinos. If these neutrinos are ab- sorbed by other U-235 nuclei, they undergo fission, releasing more neutrinos. This process continues in a chain reaction, giving a…arrow_forward
- Make to sure indicate the concept, given, formula, and your full solution.arrow_forwardplease solve question 4, nuclear physicsarrow_forwardHello please someone help me answer this problem set, thank you! Part A: A particular smoke detector contains 1.05 μCi of 241Am241Am, with a half-life of 458 years. The isotope is encased in a thin aluminum container. Calculate the mass of 241 Am in grams in the detector. Express your answer numerically in grams. Part B: Fears of radiation exposure from normal use of such detectors are largely unfounded. Identify reasons why 241 Am smoke detectors are perfectly safe. Select all that apply a. The penetrating power of αα radiation is limited. b. Ions get trapped by electrodes. c. The amount of americium is very little. d. The number of αα particles leaving the case is low. e. The detector has a plastic cover. f. The detector is housed in an aluminum case.arrow_forward
- When a plant or animal dies, its 14C content decreases with a half-life of t¹/2 = 5730 years. If an archaeologist find an ancient fire-pit containing partially consumed firewood and the 14C content of the wood is 15% of what it would be for a similar carbon sample from a present day tree, what is the approximate age of the ancient site? 24.96.91.88 Enter your numerical result below, in units of years. Aim for a precision of 2 significant figures. Your Answer: Answerarrow_forwardHello again. I have a final exam and there are 7 questions. I could not do. I asked my first question and I taked its answer. Then I ask you third question . This question is bonded the first question. The mass difference between two isotopes is sometimes just a neutron mass. The spectrometer should separate them very well. For such an isotope combination, the difference in radius should be around 1 cm. That is r2 - r1 = 1 cm. In order to achieve this, choose a magnetic field with a magnitude in Tesla (maximum magnetic field you can obtain from a conventional magnet is around 2.5 T so be far away from this value) and choose the direction also. Then determine the velocity of isotope you need. Last calculate radius r of a Pb-204 smallest isotope. and that is my 4th question below What should be the power of the voltage supply that we will use in velocity selector region?arrow_forwardHello again. I have a final exam and there are 7 questions. I could not do. I asked my first question and I taked its answer. Then I ask you third question . This question is bonded the first question. The mass difference between two isotopes is sometimes just a neutron mass. The spectrometer should separate them very well. For such an isotope combination, the difference in radius should be around 1 cm. That is r2 - r1 = 1 cm. In order to achieve this, choose a magnetic field with a magnitude in Tesla (maximum magnetic field you can obtain from a conventional magnet is around 2.5 T so be far away from this value) and choose the direction also. Then determine the velocity of isotope you need. Last calculate radius r of a Pb-204 smallest isotope. My third question is below . Now in velocity selector region, determine the magnitude and the directions of magnetic, electric fields, length and the voltage (which will create electric field) that you need to select ions with this velocity…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Half life | Radioactivity | Physics | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=IDkNlU7zKYU;License: Standard YouTube License, CC-BY