Chemistry: Principles and Practice
3rd Edition
ISBN: 9780534420123
Author: Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher: Cengage Learning
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Chapter 11, Problem 11.12QE
Interpretation Introduction
Interpretation:
The effect of sweating in cooling a person even when the atmospheric temperature is above the body temperature has to be explained.
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Chapter 11 Solutions
Chemistry: Principles and Practice
Ch. 11 - Prob. 11.1QECh. 11 - Prob. 11.2QECh. 11 - Prob. 11.3QECh. 11 - Prob. 11.4QECh. 11 - Prob. 11.5QECh. 11 - Why does a perspiring body achieve greater cooling...Ch. 11 - Prob. 11.7QECh. 11 - Prob. 11.8QECh. 11 - Prob. 11.9QECh. 11 - Prob. 11.10QE
Ch. 11 - Prob. 11.11QECh. 11 - Prob. 11.12QECh. 11 - Prob. 11.13QECh. 11 - Prob. 11.14QECh. 11 - Prob. 11.15QECh. 11 - Prob. 11.16QECh. 11 - Prob. 11.17QECh. 11 - Prob. 11.18QECh. 11 - Prob. 11.19QECh. 11 - Prob. 11.20QECh. 11 - The compounds ethanol (C2H5OH) and dimethyl ether...Ch. 11 - Prob. 11.22QECh. 11 - Prob. 11.23QECh. 11 - An amorphous solid can sometimes be converted to a...Ch. 11 - Prob. 11.25QECh. 11 - Prob. 11.26QECh. 11 - Prob. 11.27QECh. 11 - Prob. 11.28QECh. 11 - Prob. 11.29QECh. 11 - Prob. 11.30QECh. 11 - Prob. 11.31QECh. 11 - Prob. 11.32QECh. 11 - Prob. 11.33QECh. 11 - Prob. 11.34QECh. 11 - Prob. 11.35QECh. 11 - Prob. 11.36QECh. 11 - Prob. 11.37QECh. 11 - Prob. 11.38QECh. 11 - What is the enthalpy change when a 1.00-kg block...Ch. 11 - Prob. 11.40QECh. 11 - Prob. 11.41QECh. 11 - Prob. 11.42QECh. 11 - Prob. 11.43QECh. 11 - Prob. 11.44QECh. 11 - Prob. 11.45QECh. 11 - Prob. 11.46QECh. 11 - Prob. 11.47QECh. 11 - Prob. 11.48QECh. 11 - Identify the kinds of intermolecular forces...Ch. 11 - Prob. 11.50QECh. 11 - Prob. 11.51QECh. 11 - Prob. 11.52QECh. 11 - Prob. 11.53QECh. 11 - Prob. 11.54QECh. 11 - Prob. 11.55QECh. 11 - Prob. 11.56QECh. 11 - Prob. 11.57QECh. 11 - Prob. 11.58QECh. 11 - Prob. 11.59QECh. 11 - Identify the kinds of forces that are most...Ch. 11 - Arrange the following substances in order of...Ch. 11 - Arrange the following substances in order of...Ch. 11 - Prob. 11.63QECh. 11 - Silicon carbide, SiC, is a very hard, high-melting...Ch. 11 - Prob. 11.65QECh. 11 - Calcium oxide consists of a face-centered cubic...Ch. 11 - Prob. 11.67QECh. 11 - Prob. 11.68QECh. 11 - Prob. 11.69QECh. 11 - Prob. 11.70QECh. 11 - Prob. 11.71QECh. 11 - Prob. 11.72QECh. 11 - Prob. 11.73QECh. 11 - Prob. 11.74QECh. 11 - Lithium hydride (LiH) has the sodium chloride...Ch. 11 - Cesium iodide crystallizes as a simple cubic array...Ch. 11 - Palladium has a cubic crystal structure in which...Ch. 11 - Prob. 11.78QECh. 11 - Prob. 11.79QECh. 11 - Prob. 11.80QECh. 11 - Prob. 11.81QECh. 11 - Prob. 11.82QECh. 11 - Prob. 11.83QECh. 11 - Prob. 11.84QECh. 11 - Prob. 11.85QECh. 11 - The coordination number of uniformly sized spheres...Ch. 11 - Prob. 11.87QECh. 11 - Prob. 11.88QECh. 11 - Prob. 11.89QECh. 11 - Prob. 11.90QECh. 11 - Prob. 11.91QECh. 11 - Prob. 11.93QECh. 11 - Prob. 11.94QECh. 11 - A 1.50-g sample of methanol (CH3OH) is placed in...Ch. 11 - Prob. 11.96QECh. 11 - Prob. 11.97QECh. 11 - Prob. 11.98QECh. 11 - Prob. 11.99QECh. 11 - Prob. 11.100QECh. 11 - Prob. 11.103QE
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- A burning match and a bonfire may have the same temperature, yet you would not sit around a burning match on a fall evening to stay warm. Why not?arrow_forwardThe amount of heat required to melt 2 lbs of ice is twice the amount of heat required to melt 1 lb of ice. Is this observation a macroscopic or microscopic description of chemical behavior? Explain your answer.arrow_forwardWhy does sweating cool the human body?arrow_forward
- Evaporation of sweat requires energy and thus take excess heat away from the body. Some of the water that you drink may eventually be converted into sweat and evaporate. If you drink a 20-ounce bottle of water that had been in the refrigerator at 3.8 C, how much heat is needed to convert all of that water into sweat and then to vapor? (Note: Your body temperature is 36.6 oc. For the purpose of solving this problem, assume that the thermal properties of sweat are the same as for water.)arrow_forwardWill a closed container of water at 70 C or an open container of water at the same temperature cool faster on a cold winter day? Explain why.arrow_forwardIf 14.5 kJ of heat were added to 485 g of liquid water, how much would its temperature increase?arrow_forward
- Are changes in state physical or chemical changes? Explain. What type of forces must be overcome to melt or vaporize a substance (are these forces intramolecular or intermolecular)? Define the molar heat of fusion and molar heat of vaporization. Why is the molar heat of vaporization of water so much larger than its molar heat of fusion? Why does the boiling point of a liquid vary with altitude?arrow_forward1. Which of the following processes requires the largest input of energy as heat? raising the temperature of 100 g of water by 1.0 °C vaporization of 0.10 g of water at 100 °C melting 1.0 g of ice at 0 °C warming 1.0 g of ice from −50 °C to 0 °C (specific heat of ice = 2.06 J/g · K)arrow_forwardDefine the joule in terms of SI base units.arrow_forward
- Objects placed together eventually reach the same temperature. When you go into a room and touch a piece of metal in that room, it feels colder than a piece of plastic. Explain.arrow_forwardYou are camping and contemplating placing some hot objects into your sleeping bag to warm it. You warm a rock and a canteen of water, of roughly equal mass, around the fire. Which would be more effective in warming your sleeping bag? Why?arrow_forwardAn eager scientist on a hot summer day needs to determine how much ice to buy. She has a cooler which is filled with 36 cans of soda at a temperature of 86.5°F. Each can has a mass of 384 g. The scientist wants the temperature of the drinks to be 40.8°F. If there is no heat lost by the cooler and ignoring any heat lost to the soda containers, what mass mice of ice needs must she add to her cooler? Assume the temperature of the ice is 32.0 °F. The latent heat of fusion for ice is 80.0 cal/g, the specific heat of water is 1.00 cal/g. C, the specific heat of the soda is 0.900 cal/g.°C, and there are 454 grams per pound. Mice lbsarrow_forward
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