
Concept explainers
(a)
To identify: If small or large gear should be chosen.
(a)

Explanation of Solution
Introduction:
The ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load. For the work to be done easily the IMA should be as high as possible.
The IMA for the rear wheel gear is equal to the radius of the rear gear divided by the rear wheel radius. That is,
IMA =
From this formula, one can see that more is the rear gear radius; more will be the mechanical advantage. That is, the force applied on the rear gear wheel increases proportionally with the size of the rear gear radius.
So, for exerting the greatest possible force, one needs to choose the largest possible radius of the gear which ultimately implies the largest rear gear.
Conclusion:
Hence, to start the bicycle, one needs to choose the large rear gear.
(b)
To identify: The gear that should be chosen if it is required to rotate the pedals as few times as possible.
(b)

Explanation of Solution
Introduction:
The ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load. For the work to be done easily the IMA should be as high as possible.
If it is required to rotate the pedals as few times as possible then it is needed to have minimum possible chain rotation to make the wheel rotate. Choosing the small gear helps in rotating the rear wheel in minimum possible pedaling.
So, to maintain the speed by rotating the pedals as few times as possible, one has to choose the small gear.
Conclusion:
Hence, one has to choose the small gear.
(c)
To identify: The gear that should be chosen if it is required to accelerate while climbing a hill.
(c)

Explanation of Solution
Introduction:
The ideal mechanical advantage is equal to the displacement of the effort force divided by the displacement of the load. For the work to be done easily, the IMA should be as high as possible.
The IMA for the front wheel pedal is equal to the radius of the pedal divided by the radius of the front gear. That is,
IMA =
From this formula, one can see that the smaller is the front gear radius; more will be the mechanical advantage. That is the force applied on the bicycle increases inversely with the size of the front gear radius.
So, for exerting the greatest possible force, one needs to choose the smallest possible radius of the front gear, which ultimately implies the smallest front gear.
Conclusion:
Hence, to accelerate the bicycle by creating more force while climbing the hill, one needs to choose the small front gear.
Chapter 10 Solutions
Glencoe Physics: Principles and Problems, Student Edition
Additional Science Textbook Solutions
Biology: Life on Earth (11th Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
Cosmic Perspective Fundamentals
Organic Chemistry (8th Edition)
Campbell Biology (11th Edition)
Introductory Chemistry (6th Edition)
- Two long, parallel wires carry currents of I₁ = 2.70 A and I2 = 4.85 A in the directions indicated in the figure below, where d = 22.0 cm. (Take the positive x direction to be to the right.) 12 (a) Find the magnitude and direction of the magnetic field at a point midway between the wires. magnitude direction 3.91 270 μπ ⚫ counterclockwise from the +x axis (b) Find the magnitude and direction of the magnetic field at point P, located d = 22.0 cm above the wire carrying the 4.85-A current. magnitude direction Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. μT The response you submitted has the wrong sign.° counterclockwise from the +x axisarrow_forwardO Macmillan Learning The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at Vi2 = 16.1 m/s when the eagle swoops down, grabs the pigeon, and flies off. At the instant right before the attack, the eagle is flying toward the pigeon at an angle 0 = 64.3° below the horizontal and a speed of Vi,1 = 37.9 m/s. What is the speed of of the eagle immediately after it catches its prey? What is the magnitude & of the angle, measured from horizontal, at which the eagle is flying immediately after the strike? Uf = II x10 TOOLS Vi.1 Vi,2 m/sarrow_forwardWhat is the equivalent resistance if you connect a 1.7 Ohm, a 9.3 Ohm, and a 22 Ohm resistor in series? (Give your answer as the number of Ohms.)arrow_forward
- Three wires meet at a junction. One wire carries a current of 5.2 Amps into the junction, and a second wire carries a current of 3.7 Amps out of the junction. What is the current in the third wire? Give your answer as the number of Amps, and give a positive number if the current in that wire flows out of the junction, or a negative number if the current in that wire flows into the junction.arrow_forwardWhat is the equivalent resistance if you connect a 4.5 Ohm, a 6.8 Ohm, and a 15 Ohm resistor in parallel? (Give your answer as the number of Ohms.)arrow_forwardSuppose a heart defibrillator passes 10.5 Amps of current through a patient's torso for 5.0 x 10-3 seconds in order to restore a regular heartbeat. The voltage across the defibrillator is 9800 volts for the entire time that current is flowing. If 7.25 kg of body tissue is involved, with a specific heat of 3500 J/(kg°C), then what is the resulting temperature increase of the person's torso? (Give your answer as the number of degrees C.)arrow_forward
- The figure below is a cross-sectional view of a coaxial cable. The center conductor is surrounded by a rubber layer, an outer conductor, and another rubber layer. In a particular application, the current in the inner conductor is I₁ = 1.04 A out of the page and the current in the outer conductor is I2 = 2.90 A into the page. Assuming the distance d = 1.00 mm, answer the following. 4 12 (a) Determine the magnitude and direction of the magnetic field at point a. magnitude 208 direction upward (b) Determine the magnitude and direction of the magnetic field at point b. magnitude direction 238 You can approach this problem by finding the field produced by current I₁ and the field produced by I2 and then adding them vectorially. μT downwardarrow_forwardShoto, from My Hero Academia, has a power (or a “quirk”) that allows him to make large amounts of ice from nothing. Let us say that due to a fire a 361 kg steel beam is heated to 943.˚C and Shoto creates 390. kg of ice at 0.00˚C around it to cool it down. What is the final temperature of the system after the ice melts and it reaches thermal equilibrium? The specific heat of steel is 502 J/kg˚C. The specific heat of water is 4186 J/kg˚C. The latent heat of fusion for ice is 3.33⋅10^5 J/kg.arrow_forwardA 25.0 cm long organ pipe is filled with air and is open at one end and closed at the other. The speed of sound in air at 0°C is 331 m/s. What is the frequency of the fourth mode of vibration? Multiple Choice О 1,550 Hz О 1,750 Hz О 2,320 Hz О 2,720 Hz О 3,170 Hzarrow_forward
- 23.4 g of coffee beans at room temperature (18.6 °C) is mixed into 316 g of water at 96.8 °C in an effort to make coffee. The entire system is poured in a 363 g ceramic mug. Assume the mug is initally also at room temperature (18.6 °C). What is the final temperature of the mixture? The specific heat of ground coffee beans is 1670 J/kg˚C, the specific heat of water is 4186 J/kg˚C, and the specific heat of the mug is 850. J/kg˚C.arrow_forwardSnoop Dogg, in an effort to get laid back (with his mind on his money and his money on his mind) pours himself a gin and juice. He mixes 0.124 kg (about 3 shots) of gin with 0.576 kg (about a pint) of orange juice. The gin starts at 20.0˚C, room temperature. The juice is refrigerated and starts at 2.89 ˚C. What is the final temperature after mixing of the gin and juice? The specific heat of gin is 3460 J/kg˚C and the specific heat of orange juice is 3730 J/kg˚C.arrow_forwardA sword is heated up to 226 °C, it is put into a nearby barrel of water that is at 18.4 °C. What mass of water would be needed to cool the sword to 30.0˚C, bringing the system to thermal equilibrium? The sword is 35.4 kg and is made of steel. The specific heat of water is = 4186 J/kg ˚C. The specific heat of steel is = 502 J/kg ˚Carrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON





