Chapter 10.1, Problem 21SSC

To determine

Power delivered by elevator.

Answer to Problem 21SSC

Power delivered by elevator is $34496\text{W}$ .

Explanation of Solution

Given:

Total mass lift by elevator is $m=1.1\times {10}^3\text{kg}$

Distance covered is $d=40\text{m}$

Time taken by elevator is $t=12.5\text{s}$

Formula used:

Power developed is given by,

  $P=\frac{W}{t}$ ..... (1)

Calculation:

As. $W=Fd$ and $F=mg$

So,

  $\begin{array}{l}P=\frac{Fd}{t}=\frac{mgd}{t}\\ =\frac{1100\times 9.8\times 40}{12.5}\\ =34496\text{W}\end{array}$