Chapter 10, Problem 53A

To determine

Work done by D on the sled.

Answer to Problem 53A

Work done by D on the sled is $\text{12}\text{.035}\text{kJ}$

Explanation of Solution

Given:

Distance moved is $d=65.3\text{m}$

Angle of inclination is $\theta ={35}^o$

Force applied is $F=225\text{N}$

Formula used:

Work done is given by,

  $W=Fd\cos \theta$ ….. (1)

Calculation:

Substitute given values in (1)

  $\begin{array}{l}W=Fd\cos \theta \\ =225\times 65.3\times \cos {35}^o\\ =12035.4\text{J}\\ \text{=12}\text{.035}\text{kJ}\end{array}$