Chapter 10.1, Problem 2CYU

To determine

To compare the centers of L’s and R’s books.

Answer to Problem 2CYU

L’s class is reading more pages.

Explanation of Solution

Given information:

L’s books have 103, 114, 708, 98, 122 pages.

R’s books have 237, 178, 225, 206, 232 pages.

Formula used:

Mean formula is,

  $\overline{X}=\frac{{\displaystyle \sum frequency}}{N}$

Where, N is total number of items.

Calculation:

For L,

Substituting the values in the mean formula,

  $\overline{X}=\frac{103+114+708+98+122}{5}$

So,

  $\overline{X}=\frac{1135}{5}$

On solving,

  $\overline{X}=226$

Mean of L’s pages is 226

For R,

Substituting the value in the mean formula,

  $\overline{X}=\frac{237+178+225+206+232}{5}$

So,

  $\overline{X}=\frac{1078}{5}$

On solving,

  $\overline{X}=215.6$

Mean of R’s pages is 215.6

On comparing L’s and R’s book pages mean,

L’s pages mean is greater than that of R’s. Hence, L’s class is reading longer books, on an average.