A
Want to see the full answer?
Check out a sample textbook solutionChapter 10 Solutions
University Physics Volume 2
Additional Science Textbook Solutions
The Cosmic Perspective (8th Edition)
Essential University Physics: Volume 2 (3rd Edition)
College Physics (10th Edition)
College Physics
Applied Physics (11th Edition)
- Consider the circuit below. The battery has an emf of = 30.00 V and an internal resistance of r = 1,00 . (a) Find the equivalent resistance of the circuit and the current out of the battery. (b) Find the current through each resistor, (c) Find die potential drop across each resistor, (d) Find the power dissipated by each resistor, (e) Find the total power supplied by the batteries.arrow_forwardA 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the battery’s internal resistance? (b) What power is dissipated inside the battery? (c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300 kcal/kg • °C, assuming no heat escapes?arrow_forwardSemi-truck or trucks use four large 12-V batteries. The starter systemrequires 24 V, while normal operation of the truck’s other electrical components utilizes 12 V. How could the four batteries be connected to produce 24 V? To produce 12 V? Why is 24 V better than 12 V for starting the truck’s engine (a very heavy load)?arrow_forward
- Review. When a straight wire is warmed, its resistance is given by R = R0,[1 + a(T T0)] according to Equation 27.20, where a is the temperature coefficient of resistivity. This expression needs to be modified if we include the change in dimensions of the wire due to thermal expansion. For a copper wire of radius 0.100 0 mm and length 2.000 m, find its resistance at 100.0C, including the effects of both thermal expansion and temperature variation of resistivity. Assume the coefficients are known to four significant figures.arrow_forwardPower P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?arrow_forwardExplain why R=R0(1 + a?T) for the temperature variation of the resistance R of an object is not as accurate as P=P0(1 + a?T) which gives the temperature variation of resistivity P.arrow_forward
- (b) Consider a particular phone that has a battery rated at 4,000 mAh. The battery operates at a potential difference of 3.90 V. How much energy, in units of kilowatt-hours, is stored in a fully charged battery? kWh (c) If electricity costs $0.12 (or 12.0 cents) per kilowatt-hour, what is the value of the total amount of energy stored in this battery? Express your answer in cents (or 0.01 of a dollar). ¢ (d) When the phone is idle (that is, turned on but not making calls or texts, using GPS, or running any power-hungry apps), it will operate continuously for 29.2 hours from a fully charged battery, until the battery runs out. How much average current does the phone draw while idle? Express your answer in milliamperes. mAarrow_forwardA 205-kV power transmission line carrying 500 A is hung from grounded metal towers by ceramic insulators, each having a 1.40 x 109 2 resistance. (a) What is the resistance to ground of 70 of these insulators? (Assume the insulators are connected in parallel.) Ω (b) Calculate the power dissipated by 70 of them. W (c) What fraction of the power carried by the line is this? Ptotalarrow_forward(b) Consider a particular phone that has a battery rated at 2.500 mAh. The battery operates at a potential difference of 3.90 V. How much energy, in units of kilowatt-hours, is stored in a fully charged battery? 0.975-2 ✓kWh (c) If electricity costs $0.16 (or 16.0 cents) per kilowatt-hour, what is the value of the total amount of energy stored in this battery? Express your answer in cents (or 0.01 of a dollar). How can you relate the energy from part (b) to the cost per kilowatt-hour to find the total cost? (d) When the phone is idle (that is, turned on but not making calls or texts, using GPS, or running any power-hungry apps), it will operate continuously for 32.2 hours from a fully charged battery, until the battery runs out. How much average current does the phone draw while idle? Express your answer in milliamperes, MAarrow_forward
- A 2.00-nF capacitor with an initial charge of 4.28 µC is discharged through a 2.72-kΩ resistor. (a) Calculate the current in the resistor 9.00 µs after the resistor is connected across the terminals of the capacitor. (Let the positive direction of the current be define such that dQ/dt>0.) mA, (b) What charge remains on the capacitor after 8.00 µs? uc, (c) What is the (magnitude of the) maximum current in the resistor? A.arrow_forward() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE, R3 ww The emf source, E = 2.1 V, of the circuit shown in the figure has negligible internal resistance. The resistors have resistances R = 1.91 and R = 5.9N. The capacitor has a capacitance C = 5.8 uF. R1 B) What is the charge Q on the capacitor in units of microcoulomb? Answer:arrow_forwardA 10 uF capacitor is connected in series to a 2. 0 MΩ resistor and a 100V power source. (a) Calculate the time constant of this circuit. (b) What is the final charge on the capacitor? (c) 63% charge and (d) 95% charged? Use the formula: q=qf (1-e -t/RC)arrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning