University Physics Volume 2
18th Edition
ISBN: 9781938168161
Author: OpenStax
Publisher: OpenStax
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Chapter 10, Problem 35P
Consider the circuit shown below. The terminal voltage of the battery is V = 18.00 V. (a) Find the equivalent resistance of the circuit, (b) Find the current through each resistor, (c) Find the potential drop across each resistor, (d) Find the power dissipated by each resistor, (e) Find the power supplied by the battery.
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Students have asked these similar questions
In a circuit, all the power delivered by the battery must be dissipated by the elements to the circuit. This is
simply a statement of the conservation of energy. How much energy dissipated depends on the resistance of
the element and the voltage across the resistor, or the current through it. The relevant equations for the
problems are as follows. For a circuit element, the power dissipated (or generated) is P = IV, where Vand I are
the voltage across and current through a circuit element. We know that a resistor obeys OhmA ¢A^A^'s Law
V=IR, which means that for a resistor, the power dissipated is P = I*R = V²/R.
Consider the following two circuits with identical batteries and re-
sistors.
А
В
C
R
R
R RS
R
If the power dissipated by the resistor in circuit A is P, what is the
power dissipated by one resistor in circuit B?
If the power dissipated by the resistor in circuit A is P, what is the
power dissipated by one resistor in circuit C?
Consider the circuit shown below. The terminal
voltage of the battery is V = 18.00 V.
(a)Find the equivalent resistance of the circuit.
(b)Find the current through each resistor.
(c) Find the potential drop across each resistor.
(d)Find the power dissipated by each resistor.
(e) Find the power supplied by the battery.
R
= 4.00 N
V = 18.00 V
R2 = 1.00 N
= 4.00 N
Look at a circuit
made up of a
resistor, a battery, a
capacitor, and a
switch. Take the time
constant of the circuit
to be 3.12 seconds.
So if the resistor has
a current of 420 mA
and a voltage of 12.0
V when the switch is
closed, calculate the
capacitance of the
capacitor.
Chapter 10 Solutions
University Physics Volume 2
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Ohm's law Explained; Author: ALL ABOUT ELECTRONICS;https://www.youtube.com/watch?v=PV8CMZZKrB4;License: Standard YouTube License, CC-BY