Chapter 10, Problem 167AP

Interpretation Introduction

Interpretation:

The molar volume(in L) of an ideal gas at $6.0\text{ mmHg}$, $220\text{K}$ is to be calculated.

Concept introduction:

The standard form of an ideal gas equation is as follows:

$PV=nRT$

Here, $P$ is the pressure, $V$ is the volume, $n$ is the number of moles, $R$ is gas constant, and $T$ is the temperature.

The molar volume, represented by V_m, is the volume occupied by one mole of a substance, which can be a chemical element or a chemical compound at Standard Temperature and Pressure (STP) as

${\text{V}}_{\text{m}}\text{ = Atomic weight }\times \text{ Molar mass / Density}$

The conversion of temperature from degree Celsius to kelvin can be done by using the formula given below:

$T\left(\text{K}\right)=T\left(°\text{C}\right)+273.15$