Introduction To Health Physics
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ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
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Chapter 10, Problem 10.5P
To determine
Attenuation factor for 1-MeV gamma rays.
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CSDA range
Determine the expected range of 2 MeV beta radiation in polyethylene, Aluminium and air. Use the ESTAR database on the NIST website
to find the CSDA ranges (to 4 significant figures):
R(px) for polyethylene = 9.375E-01
✓g/cm²
R(px) for Al=
1.224E+00
✓ g/cm²
R(px) for air-
1.094E+00
x g/cm²
Looking at the 3 values you have found, the statement in the lab notes that the range is 'inversely proportional to the density p of the
material and not dependent on its structure or any other properties' is
a useful rough approximation because the px values are similar even if not exactly the same
The values given are density times thickness (px). To find the actual range (x) we just divide by the density.
The linear absorption coefficient for 5-MeV gamma rays in lead is 78 m-1. Find the thickness of lead required to reduce by one-fourth the intensity of beam of such gamma rays.
question 4 please
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- Q.4. (b) The linear absorption coefficient of lead for 1.0 MeV gamma rays is 74 m¹. Calculate the half value Thickness and Thickness of lead to reduce the GO intensity of gamma rays to of its original value. 100 (log 2 = 0.693 and log 10 = 2.30) -|arrow_forwardPlease provide Handwritten answer. Two 13.3 mg radium tubes are arranged in a line with their centers 5.5 cm apart. A weaker source is placed midway between them. How much radium should be in this latter source to produce the same dose rates to points opposite each of the sources at a distance of 2.0 cm away from the line. Assume sources 1.35 cm active length 1.0 mm Pt.arrow_forwardA small 10-gram source of cobalt-60 is in a vacuum. (a) What is the activity of the cobalt-60source in Bq? (b) What is the actual gamma-ray flux in cm2-s-1 at a point of measurement500 cm from the source due to the cobalt-60 emitted gamma-rays? (c) If the backgroundgamma-ray flux in the vicinity of the 10-g source is 7.8×107cm-2-s-1, what is the totalgamma-ray flux at the point of measurement, including the background? (d) What thicknessof a lead shield in cm would have to be placed between the source and the point ofmeasurement to reduce the total of the background plus the uncollided gamma-ray flux fromthe cobalt-60 source to 1.00×108cm-2-s-1 at that point? (I've attempted part a of the problem and don't know how to continue)arrow_forward
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