Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Chapter 10, Problem 10.18P
To determine
Fraction of the dose equivalent from an unshielded source
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A 95 kgkg patient swallows a 33 μCiμCi beta emitter with a half-life of 5.0 days, and the radioactive nuclei are quickly distributed throughout his body. The beta particles are emitted with an average energy of 0.35 MeVMeV, 90%% of which is absorbed by the body.
What dose equivalent does the patient receive in the first week?
A 85 kg patient swallows a 31 μCi beta emitter with a half-life of 5.0 days, and the radioactive nuclei are quickly distributed throughout his body. The beta particles are emitted with an average energy of 0.35 MeV, 90% of which is absorbed by the body.
What dose equivalent does the patient receive in the first week in mSv?
A small region of a cancer patient’s brain is exposed for 24.0 min to 475 Bq of radioactivity from ⁶⁰Co for treatment of atumor. If the brain mass exposed is 1.858 g and β⁻ each particle emitted has an energy of 5.05X10⁻¹⁴J, what is the dose in rads?
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- Calculate the dose in Sv to the chest at a patient given an xray under the following conditions. The xray beam intensity is 1.50 W/m2, the area of the chest exposed is 0.0750 m2 35.0% of the xrays are absorbed in 20.0 kg of tissue, and the exposure time is 0.250 s.arrow_forwardA beam of 168MeV nitrogen nuclei is used for cancer therapy. If this beam is directed onto a 0.200kg tumor and gives it a 2.00Sv dose, how many nitrogen nuclei were stopped? (Use an RBE of 20 for heavy ions.)arrow_forwardData from the appendices and the periodic table may be needed for these problems. A 60Co source is labeled 4.00 mCi, but its present activity is found to be 1.85107Bq. (a) What is the present activity in mCi? (b) How long ago did it actually have a 4.00—mCi activity?arrow_forward
- Find the radiation dose in Gy for: (a) A 10-mSv fluoroscopic X-ray series, (b) 50 mSv of skin exposure by an a emitter, (c) 160 mSv of and rays from the 40K in your body.arrow_forwardWhat time interval elapses while 90.0% of the radioactivity of a sample of 3372As disappears as measured by its activity? The half-life of 3372As is 26 h.arrow_forwardFind the radiation dose in Gy for: (a) A 10mSv fluoroscopic xray series. (b) 50 mSv of skin exposure by an emitter. (c) 160 mSv of and rays from the 40K in your body.arrow_forward
- (a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forwardWhat is the dose in Sv in a cancer treatment that exposes the patient to 200 Gy of rays?arrow_forwardSuppose one load irradiation plant uses a 137Cs source while another uses an equal activity of 60Co. Assuming equal fractions of the (rays from the sources are absorbed, why is more time needed to get the same dose using me 137Cs source?arrow_forward
- Large amounts of 65Zn are produced in copper exposed to accelerator beams. While machining contaminated copper, a physicist ingests 50.0 Ci of 65Zn. Each 65Zn decay emits an average ray energy of 0.550 MeV, 40.0% of which is absorbed in the scientist’s 75.0kg body. What dose in mSv is caused by this in one day?arrow_forwardIf everyone in Australia received an extra 0.05 mSv per year of radiation, what would be the increase in the number of cancer deaths per year? (Assume that time had elapsed for the effects to become apparent.) Assume that there are 200104 deaths per Sv of radiation per year. What percent at the actual number of cancer deaths recorded is this?arrow_forward(a) Calculate the energy released in the neutroninduced fission (similar to the spontaneous fission in Example 32.3) n+238U96Sr+140Xe+3n, given m(96Sr)=95.921750u and m(140Xe)=139.92164. (b) This result is about 6 MeV greater than the result for spontaneous fission. Why? (c) Con?rm that the total number at nucleons and total charge are conserved in this reaction.arrow_forward
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