General, Organic, and Biological Chemistry: Structures of Life (5th Edition)
5th Edition
ISBN: 9780321967466
Author: Karen C. Timberlake
Publisher: PEARSON
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Chapter 10, Problem 10.49AQAP
Consider the reaction: (10.3)
a Write the equilibrium constant expression
b Whet is the numerical value of
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14.55 Heating solid sodium bicarbonate in a closed vessel establishes the following equilibrium: (15.5)
2NaHCO3(s) = N22CO3(s) + H20(g) + CO2(8)
What would happen to the equilibrium position if
(a) CO2 gas were added to the system,
(b) Na2CO3 were removed from the system,
(c) NaHCO3 were removed from the system.
The temperature remains constant in each case.
At high temperatures nitrogen (N2) and oxygen (O2) will react to form NO.N2(g) + O2(g) ⇆ 2 NO(g) (4.1)The value for the equilibrium constant for reaction 4.1 is KC = 2.7 x 10^-17 at some temperature T.A system initially has [N2] = 0.0800 M and [O2] = 0.0500 M. There is no NO initially present inthe system. Find the value for [NO] that will be present at equilibrium.
12 (9)
H₂ (9)
In which direction will equilibrium shift if
H2 gas is added to the system?
+
HI is removed as soon as formed?
2HI
(g)
Chapter 10 Solutions
General, Organic, and Biological Chemistry: Structures of Life (5th Edition)
Ch. 10.1 - What is meant by the rate of a reaction? Why does...Ch. 10.1 - How does a catalyst affect the activation energy?...Ch. 10.1 - Prob. 10.3QAPCh. 10.1 - Prob. 10.4QAPCh. 10.1 - Prob. 10.5QAPCh. 10.1 - Prob. 10.6QAPCh. 10.2 - Prob. 10.7QAPCh. 10.2 - Prob. 10.8QAPCh. 10.2 - Prob. 10.9QAPCh. 10.2 - Prob. 10.10QAP
Ch. 10.2 - Prob. 10.11QAPCh. 10.2 - Prob. 10.12QAPCh. 10.3 - Prob. 10.13QAPCh. 10.3 - Prob. 10.14QAPCh. 10.3 - Prob. 10.15QAPCh. 10.3 - Prob. 10.16QAPCh. 10.3 - Prob. 10.17QAPCh. 10.3 - Prob. 10.18QAPCh. 10.3 - Prob. 10.19QAPCh. 10.3 - Prob. 10.20QAPCh. 10.4 - Prob. 10.21QAPCh. 10.4 - Prob. 10.22QAPCh. 10.4 - Prob. 10.23QAPCh. 10.4 - Prob. 10.24QAPCh. 10.4 - Prob. 10.25QAPCh. 10.4 - Prob. 10.26QAPCh. 10.4 - Prob. 10.27QAPCh. 10.4 - The Kc for the following reaction at 225C is...Ch. 10.5 - Prob. 10.29QAPCh. 10.5 - Ammonia is produced by reacting nitrogen gas and...Ch. 10.5 - Prob. 10.31QAPCh. 10.5 - Prob. 10.32QAPCh. 10.5 - Prob. 10.33QAPCh. 10.5 - Prob. 10.34QAPCh. 10.5 - Prob. 10.35QAPCh. 10.5 - Prob. 10.36QAPCh. 10.5 - Prob. 10.37QAPCh. 10.5 - Prob. 10.38QAPCh. 10 - Prob. 10.39UTCCh. 10 - Prob. 10.40UTCCh. 10 - Prob. 10.41UTCCh. 10 - Prob. 10.42UTCCh. 10 - Prob. 10.43UTCCh. 10 - Prob. 10.44UTCCh. 10 - Prob. 10.45AQAPCh. 10 - For each of the following changes at equilibrium,...Ch. 10 - Prob. 10.47AQAPCh. 10 - Prob. 10.48AQAPCh. 10 - Consider the reaction: (10.3) 2NH3gN2g+3H2g a...Ch. 10 - Consider the reaction: (10.3) 2SO2g+O2g2SO3g a...Ch. 10 - Prob. 10.51AQAPCh. 10 - Prob. 10.52AQAPCh. 10 - According to Le Châtelier’s principle, does the...Ch. 10 - Prob. 10.54AQAPCh. 10 - Prob. 10.55AQAPCh. 10 - Prob. 10.56AQAPCh. 10 - Prob. 10.57CQCh. 10 - Prob. 10.58CQCh. 10 - Prob. 10.59CQCh. 10 - Prob. 10.60CQCh. 10 - Prob. 10.61CQCh. 10 - Prob. 10.62CQCh. 10 - Prob. 10.63CQCh. 10 - Indicate if you would increase or decrease the...
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- Consider the following reaction: 2NH3 (9) N2(g) + 3H₂(g) If 0.000372 moles of NH3(g), 0.392 moles of N₂, and 0.312 moles of H₂ are at equilibrium in a 19.9 L container at 925 K, the value of the equilibrium constant, Kc, isarrow_forwardIf at 400°C the equilibrium constant for the reaction NO2(g) + H2(g) = NO(g) + H₂O(g) has Kp = 7.28 x 10-6, what is AG for this reaction at 400°C? (1) 66.2 kJ/mol O (3) 654 kJ/mol O (4) 388 kJ/mol O (2) 39.3 kJ/mol # 3 A Moving to the next question prevents changes to this answer. E $ 4 R % 5 T C 6 MacBook Pro Y & 7 U * 8 - 9 K 0 0 L P Question 2 of + 11arrow_forward2.8. You are given a box containing NH3, N₂, and H₂ at equilibrium at 1000 K. The contents are analyzed, and the following concentrations are found: NH3 = 1.02 mol/L. N₂ = 1.03 mol/L, and H₂ = 1.62 mol/L. Calculate the value of K for the reaction: 2NH3(8) N₂ 2(g) + 3H2(g) =arrow_forward
- 3.6arrow_forward1:18 Consider the following reaction at equilibrium CO(g) + H₂O(g) Question 4 of 16 A) reactants B) products C) no change = If CO(g) is removed, in which direction will the equilibrium shift? CO₂(g) + H₂(g) Submit Tap here or pull up for additional resourcesarrow_forwardConsider the following equilibrium for which H = -114.44: 4 HCl(g) + O2(g) 2 Cl2(g) + 2 H2O(g) How will each of the following changes affect an equilibrium mixture of the 4 gases in this reaction?(a) O2(g)) is added to the system. which will happen? the equilibrium will not shift the equilibrium will shift toward product but Keq will not change the equilibrium will shift toward reactant but Keq will not change the equilibrium will shift toward product and Keq will increase the equilibrium will shift toward reactant and Keq will decrease (b) The reaction mixture is cooled. the equilibrium will not shift the equilibrium will shift toward product but Keq will not change the equilibrium will shift toward reactant but Keq will not change the equilibrium will shift toward product and Keq will increase the equilibrium will shift toward reactant and Keq will decrease (c) The volume of the reaction vessel is reduced by 50%. (d) A catalyst is added to the reaction mixture. (e)…arrow_forward
- 2. Given the following equilibrium systems, determine the effect on the equilibrium when the named "stress" is applied. Normally the addition of solids or liquids to an equilibrium has no effect. a 2 NH3 (g) + 92.5 kJ 5 N2(9) + 3 H2 (9) Stress Equilibrium Shift 1 Remove N2 (9) 2 Add NH3 (9) 3 Remove H2 (9) 4 Remove NH3 (9) Add O2 (g) 6 Decrease Pressure 7 Add Heat b Ag2CO3 (s) 5 2 Ag1+ (aq) + CO32 (aq) Stress Equilibrium Shift 1 Add CO32" (aq) Remove Ag* (aq) 1+ 2 3 Add A92CO3 (s) 4 Add heat CANNOT ANSWER 5 Evapourate water offarrow_forward1:18 Question 1 of 16 Consider the following chemical reaction at equilibrium: 2NO₂(g) = N₂O4(9) A) reactants If the container's volume is increased by a factor of 2, in which direction will the equilibrium shift? B) product Submit C) neither the reactants nor the product Tap here or pull up for additional resourcesarrow_forward(10b) The equilibrium constant, Kc, for the following reaction is 1.29×10-2 at 600K. COCl2(g) CO(g) + Cl2(g)If an equilibrium mixture of the three gases in a 11.8 L container at 600K contains 0.303 mol of COCl2(g) and 0.320 mol of CO, the equilibrium concentration of Cl2 is M. (25a) The equilibrium constant, K, for the following reaction is 1.75×10-2 at 609 K.COCl2 (g) CO (g) + Cl2 (g) An equilibrium mixture of the three gases in a 14.0 L container at 609 K contains 0.209 M COCl2, 6.04×10-2 M CO and 6.04×10-2 M Cl2. What will be the concentrations of the three gases once equilibrium has been reestablished, if the equilibrium mixture is compressed at constant temperature to a volume of 5.82 L? [COCl2] = M [CO] = M [Cl2] = Marrow_forward
- Consider the following equilibrium for which H = -114.44: 4 HCl(g) + O2(g) 2 Cl2(g) + 2 H2O(g) How will each of the following changes affect an equilibrium mixture of the 4 gases in this reaction?(a) O2(g)) is added to the system. The equilibrium will not shift The equilibrium will shift toward product but Keq will not change The equilibrium will shift toward reactant but Keq will not change The equilibrium will shift toward product but Keq will will increase The equilibrium will shift toward reactant but Keq will decrease(b) The reaction mixture is cooled. (c) The volume of the reaction vessel is reduced by 50%.arrow_forwardEe.38.arrow_forwardAt 475 oC, Keq = 0.230 for the reaction: 1/3 NO2(g) + 1/3 N2O(g) (equilibrium arrows) NO(g) (a) What is the value of Keq for the reaction NO(g) 1/3 NO2(g) + 1/3 N2O(g)?Keq = .(b) What is the value of Keq for the reaction NO2(g) + N2O(g) 3 NO(g)?Keq = .(c) What is the value of Keq for the reaction 3 NO(g) NO2(g) + N2O(g)?Keq = .arrow_forward
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