Major product for the give reaction is to be predicted. Concept introduction: Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The S N 2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

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Answer 1

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Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

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CS2(g) →CS(g) + S(g) The rate law is Rate = k[CS2] where k = 1.6 × 10−6 s−¹. S What is the concentration of CS2 after 5 hours if the initial concentration is 0.25 M?

CS2(g) → CS(g) + S(g) The rate law is Rate = k [CS2] where k = 1.6 × 10-6 s−1. S Calculate the half-life.

Answer 2

Question

Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

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Answer 3

Question

Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

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Answer 4

Question

Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

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Answer 5

Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

Answer 6

Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

Answer 7

Chapter 10, Problem 10.23P

Interpretation Introduction

Interpretation:

Major product for the give reaction is to be predicted.

Concept introduction:

Under neutral or basic conditions, a nucleophile attacks an epoxide at the less highly alkyl-substituted C atom of the ring, from the side opposite the O atom. The SN2 reaction proceeds faster at carbon with less steric hindrance. The strong nucleophile attacks from the backside and the substituents remain bonded to the carbon atom.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 10 - Prob. 10.1P Ch. 10 - Prob. 10.2P Ch. 10 - Prob. 10.3P Ch. 10 - Prob. 10.4P Ch. 10 - Prob. 10.5P Ch. 10 - Prob. 10.6P Ch. 10 - Prob. 10.7P Ch. 10 - Prob. 10.8P Ch. 10 - Prob. 10.9P Ch. 10 - Prob. 10.10P

Solution Summary: The author explains that the major product for the given reaction is predicted from the mechanism of the reaction.

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