As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s 2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s 2 . The unit of mass this is the slug, which is 14.59 kg. Thus, BE unit of force = 1 pound = ( slug ) ( ft / s 2 ) Use thisinformation to confirm that BE unit of force = 4 .45×SI unit of force 1 pound = 4 .45 newton
As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s 2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s 2 . The unit of mass this is the slug, which is 14.59 kg. Thus, BE unit of force = 1 pound = ( slug ) ( ft / s 2 ) Use thisinformation to confirm that BE unit of force = 4 .45×SI unit of force 1 pound = 4 .45 newton
Solution Summary: The author explains that the scientific system of measurement is called the systeme internationale d’Unites and it is abbreviated SI.
As mentioned on page 13, the MCO was lost because of a mix-up in the units used to calculate the force needed to correct its trajectory. Ground-based computers generated the forte correction file. On September 29, 1999, it was discovered that the fortes reported by the ground-based use in MCOnavigation software were by a factor of 4.45. The erroneous trajectory brought MCO 56 km above thesurface of Mars: the correct trajectory would have brought the MCO approximately 250 km above the surface. At 250 km, the NCO would have successfully entered the desired elliptic orbit. The data contained in the force correction files were delivered in lb-sec instead of the required Sl units of newton-sec for the MCO navigation software. The newton is the SI unit of force is described in Appendix B. The British Engineering (gravitational) system uses a pound (b) as a unit of force and ft / s2 as a unit of acceleration. In turn. the pound is defined as the of on unit of mass at a caused by gravity 32.174ft / s2. The unit of mass this is the slug, which is 14.59 kg. Thus,
BE unit of force = 1 pound =
(
slug
)
(
ft / s
2
)
Use thisinformation to confirm that
BE unit of force = 4
.45×SI unit of force
Q1: Curved Arrows, Bronsted Acids & Bases, Lewis Acids & Bases
Considering the following reactions:
a) Predict the products to complete the reactions.
b) Use curved electron-pushing arrows to show the mechanism for the reaction in
the forward direction. Redraw some of the compounds to explicitly illustrate all
bonds that are broken and all bonds that are formed.
c) Label Bronsted acids and bases in the left side of the reactions. Label conjugate
acids and bases in the right side of the reactions.
d) Label Lewis acids and bases, nucleophiles and electrophiles in the left side of the
reactions.
A.
+
OH
CH30:
OH
B.
+
HBr
C.
H₂SO4
D.
CF 3.
CH 3
+
HCI
N
H
fluoxetine
antidepressant
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JDownload
Don't used Ai solution
Chapter 1 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
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What are CHNOPS? These Chemical Elements = 98% of Life | Biology | Biochemistry; Author: Socratica;https://www.youtube.com/watch?v=w90wFlR53VM;License: Standard YouTube License, CC-BY