(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
Solution Summary: The author explains the conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The boiling point of water in A0 if melting point of ammonia is 0 A0 or − 77.75 C0 and boiling point of ammonia is 100 A0 or - 33.35 C0 needs to be determined.
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oA)– Tlower(in oA))(Thigher( in oA)– Tlower(in oA)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
Interpretation Introduction
(b)
Interpretation:
The absolute zero temperature in A0 needs to be determined, if melting point of ammonia is 0 A0 or − 77.75 C0 and boiling point of ammonia is 100 A0 or - 33.35 C0
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oA)– Tlower(in oA))(Thigher( in oA)– Tlower(in oA)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
In mass spectrometry, alpha cleavages are common in molecules with
heteroatoms. Draw the two daughter ions that would be observed in the
mass spectrum resulting from an alpha cleavage of this molecule.
+
NH2
Q
Draw Fragment with m/z of 72
Chapter 1 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)