A tabulation of datalists the following equation for calculating the densities ( d ) of solutions of naphthalene benzene at 30 °C as a function of the mass percent of naphthalene. d ( g / c m 3 ) = 1 1.153 − 1.82 × 10 − 3 ( % N ) + 1.08 × 10 − 6 ( % N ) 2 Use the equation above to calculate (a) the density of pure benzene at 30 °C; (b) the density of pure naphthalene at 30 °C; (C) the density of a solution at 30 °Cthat is 1.15% naphthalene; (d) the mass percent of naphthalene in a solution that has a density of 0.952 g/cm 2 at 30 °C. [ Hint: For (d), you need to the quadratic formula. See Section A-3 of Appendix A.]
A tabulation of datalists the following equation for calculating the densities ( d ) of solutions of naphthalene benzene at 30 °C as a function of the mass percent of naphthalene. d ( g / c m 3 ) = 1 1.153 − 1.82 × 10 − 3 ( % N ) + 1.08 × 10 − 6 ( % N ) 2 Use the equation above to calculate (a) the density of pure benzene at 30 °C; (b) the density of pure naphthalene at 30 °C; (C) the density of a solution at 30 °Cthat is 1.15% naphthalene; (d) the mass percent of naphthalene in a solution that has a density of 0.952 g/cm 2 at 30 °C. [ Hint: For (d), you need to the quadratic formula. See Section A-3 of Appendix A.]
Solution Summary: The author explains that the density of pure benzene at 30circ C needs to be determined.
A tabulation of datalists the following equation for calculating the densities (d) of solutions of naphthalene benzene at 30 °C as a function of the mass percent of naphthalene.
d
(
g
/
c
m
3
)
=
1
1.153
−
1.82
×
10
−
3
(
%
N
)
+
1.08
×
10
−
6
(
%
N
)
2
Use the equation above to calculate (a) the density of pure benzene at 30 °C; (b) the density of pure naphthalene at 30 °C; (C) the density of a solution at 30 °Cthat is 1.15% naphthalene; (d) the mass percent of naphthalene in a solution that has a density of 0.952 g/cm2 at 30 °C. [Hint: For (d), you need to the quadratic formula. See Section A-3 of Appendix A.]
Predict products for the Following organic rxn/s by
writing the structurels of the correct products. Write
above the line provided"
your answer
D2
①CH3(CH2) 5 CH3 + D₂ (adequate)"
+
2
mited)
19
Spark
Spark
por every item.
4 CH 3 11
3 CH 3 (CH2) 4 C-H + CH3OH
CH2 CH3 + CH3 CH2OH
0
CH3
fou
+
KMnDy→
C43
+ 2 KMn Dy→→
C-OH
")
0
C-OH
1110
(4.)
9+3
=C
CH3
+ HNO 3
0
+ Heat>
+ CH3 C-OH + Heat
CH2CH3
- 3
2
+ D Heat H
3
CH 3 CH₂ CH₂ C = CH + 2 H₂ →
2
2
When 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.
Q6: Using acetic acid as the acid, write the balanced chemical equation for the protonation of
the two bases shown (on the -NH2). Include curved arrows to show the mechanism.
O₂N-
O₂N.
-NH2
-NH2
a) Which of the two Bronsted bases above is the stronger base? Why?
b) Identify the conjugate acids and conjugate bases for the reactants.
c) Identify the Lewis acids and bases in the reactions.
Chapter 1 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
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