A tabulation of datalists the following equation for calculating the densities ( d ) of solutions of naphthalene benzene at 30 °C as a function of the mass percent of naphthalene. d ( g / c m 3 ) = 1 1.153 − 1.82 × 10 − 3 ( % N ) + 1.08 × 10 − 6 ( % N ) 2 Use the equation above to calculate (a) the density of pure benzene at 30 °C; (b) the density of pure naphthalene at 30 °C; (C) the density of a solution at 30 °Cthat is 1.15% naphthalene; (d) the mass percent of naphthalene in a solution that has a density of 0.952 g/cm 2 at 30 °C. [ Hint: For (d), you need to the quadratic formula. See Section A-3 of Appendix A.]
A tabulation of datalists the following equation for calculating the densities ( d ) of solutions of naphthalene benzene at 30 °C as a function of the mass percent of naphthalene. d ( g / c m 3 ) = 1 1.153 − 1.82 × 10 − 3 ( % N ) + 1.08 × 10 − 6 ( % N ) 2 Use the equation above to calculate (a) the density of pure benzene at 30 °C; (b) the density of pure naphthalene at 30 °C; (C) the density of a solution at 30 °Cthat is 1.15% naphthalene; (d) the mass percent of naphthalene in a solution that has a density of 0.952 g/cm 2 at 30 °C. [ Hint: For (d), you need to the quadratic formula. See Section A-3 of Appendix A.]
Solution Summary: The author explains that the density of pure benzene at 30circ C needs to be determined.
A tabulation of datalists the following equation for calculating the densities (d) of solutions of naphthalene benzene at 30 °C as a function of the mass percent of naphthalene.
d
(
g
/
c
m
3
)
=
1
1.153
−
1.82
×
10
−
3
(
%
N
)
+
1.08
×
10
−
6
(
%
N
)
2
Use the equation above to calculate (a) the density of pure benzene at 30 °C; (b) the density of pure naphthalene at 30 °C; (C) the density of a solution at 30 °Cthat is 1.15% naphthalene; (d) the mass percent of naphthalene in a solution that has a density of 0.952 g/cm2 at 30 °C. [Hint: For (d), you need to the quadratic formula. See Section A-3 of Appendix A.]
LTS
Solid:
AT=Te-Ti
Trial 1
Trial 2
Trial 3
Average
ΔΗ
Mass water, g
24.096
23.976
23.975
Moles of solid, mol
0.01763
001767
0101781
Temp. change, °C
2.9°C
11700
2.0°C
Heat of reaction, J
-292.37J -170.473
-193.26J
AH, kJ/mole
16.58K 9.647 kJ 10.85 kr
16.58K59.64701
KJ
mol
12.35k
Minimum AS,
J/mol K
41.582
mol-k
Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn &
Show your calculations for:
AH in J and then in kJ/mole for Trial 1:
qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J
qsin =
qrxn =
292.35 292.37J
AH in J = 292.375 0.2923kJ
0.01763m01
=1.65×107
AH in kJ/mol =
=
16.58K
0.01763mol
mol
qrx
Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con
Kelvin.)
AS=AHIT
(1.65×10(9.64×103) + (1.0
Jimai
For the compound: C8H17NO2
Use the following information to come up with a plausible structure:
8
This compound has "carboxylic acid amide" and ether functional groups.
The peaks at 1.2ppm are two signals that are overlapping one another.
One of the two signals is a doublet that represents 6 hydrogens; the
other signal is a quartet that represents 3 hydrogens.
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Chapter 1 Solutions
General Chemistry: Principles and Modern Applications (11th Edition)
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