a.
Explanation of Solution
Given,
The clock rate and the Cycles Per Instruction (CPI) of the processor P1 is 3 GHz and 1.5 respectively.
The clock rate and the CPI of the processor P2 is 2.5 GHz and 1.0 respectively.
The clock rate and the CPI of the processor P3 is 4 GHz and 2.2 respectively.
The performance of the processor in terms of instructions per second can be calculated using the following formula is given below:
Substitute, “
Thus, the performance of the processor P1 is
Substitute, “
Thus, the performance of the processor P1 is
Substitute, “
Thus, the performance of the processor P1 is
By comparing the above performances of the processors, it is concluded that the processor P1 is having highest performance.
b.
Explanation of Solution
Given,
The clock rate and the Cycles Per Instruction (CPI) of the processor P1 is 3 GHz and 1.5 respectively.
The clock rate and the CPI of the processor P2 is 2.5 GHz and 1.0 respectively.
The clock rate and the CPI of the processor P3 is 4 GHz and 2.2 respectively.
Time taken by each processor to execute the required program is 10 seconds.
The number of cycles of the processor per 10 seconds can be calculated using the following formula is given below:
Substitute, “
Thus, the number of cycles of the processor P1 per 10 seconds is
Substitute, “
Thus, the number of cycles of the processor P2 per 10 seconds is
Substitute, “
Thus, the number of cycles of the processor P3 per 10 seconds is
The number of instructions of the processor per 10 seconds can be calculated using the following formula is given below:
Substitute, “
Thus, the number of instructions of the processor P1 per 10 seconds is
Substitute, “
Thus, the number of instructions of the processor P2 per 10 seconds is
Substitute, “
Thus, the number of instructions of the processor P3 per 10 seconds is
c.
Explanation of Solution
Given,
The clock rate and the Cycles Per Instruction (CPI) of the processor P1 is 3 GHz and 1.5 respectively.
The clock rate and the CPI of the processor P2 is 2.5 GHz and 1.0 respectively.
The clock rate and the CPI of the processor P3 is 4 GHz and 2.2 respectively.
The number of instructions of the processor per 10 seconds can be calculated using the following formula is given below:
Substitute, “
Thus, the number of instructions of the processor P1 per 10 seconds is
Substitute, “
Thus, the number of instructions of the processor P2 per 10 seconds is
Substitute, “
Thus, the number of instructions of the processor P3 per 10 seconds is
The CPInew is calculated using the formula
Substitute, “1.5” for “CPIold” is given below:
Thus, the CPInew of the processor P1 is
Substitute, “1.0” for “CPIold” is given below:
Thus, the CPInew of the processor P2 is
Substitute, “4.0” for “CPIold” is given below:
Thus, the CPInew of the processor P3 is
The required clock rate cam be calculated using a function f and the required formula is as follows:
Substitute, “
Thus, the required function of the processor P1 is
Substitute, “
Thus, the required function of the processor P2 is
Substitute, “
Thus, the required function of the processor P3 is
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Chapter 1 Solutions
Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
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I need help fixing errors on the VHDL so that the counter counts up from 1 to 6 of both files, as the attached image shows when compiled. Counter_1_to_6.vhdl: library IEEE;use IEEE.STD_LOGIC_1164.ALL;use IEEE.STD_LOGIC_ARITH.ALL;use IEEE.STD_LOGIC_UNSIGNED.ALL; entity Counter_1_to_6 is Port ( clk : in STD_LOGIC; -- Clock input reset : in STD_LOGIC; -- Asynchronous reset count : out STD_LOGIC_VECTOR (2 downto 0) -- 3-bit output (1 to 6) );end Counter_1_to_6; architecture Behavioral of Counter_1_to_6 is signal counter_reg : STD_LOGIC_VECTOR (2 downto 0) := "001"; -- Start at 1begin process(clk, reset) begin if reset = '1' then counter_reg <= "001"; -- Reset to 1 elsif rising_edge(clk) then if counter_reg =…arrow_forwardI need help with this problem, and an explanation for the solution is described below (Fundamentals of Computer Engineering: ModelSim - standard edition). I need help modifying the below codes of "VHDL so that the counter counts up from 1 to 7" of both files into "VHDL to design a counter to count up from 1 to 6". (Fundamentals of Computer Engineering: ModelSim - standard edition). Counter_1_to_7.vhdl: library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity Counter_1_to_7 is Port ( clk : in STD_LOGIC; -- Clock input reset : in STD_LOGIC; -- Asynchronous reset count : out STD_LOGIC_VECTOR (2 downto 0) -- 3-bit output (1 to 7) ); end Counter_1_to_7; architecture Behavioral of Counter_1_to_7 is signal counter_reg : STD_LOGIC_VECTOR (2 downto 0) := "001"; -- Start at 1 begin process(clk, reset) begin if reset = '1' then counter_reg <= "001"; -- Reset to 1 elsif rising_edge(clk) then if…arrow_forwardCREATE DATABASE H Vybo PAP PT AUTO INCREMENT PEMARY FLY CHARDOX Age N GIMM ARCH Contacte WCHO CREATE TABLE Typ AUTO INCEMENT MARY CREATE SALE Patan T GN AUTO CEMENT PAMARY DDATE Test T CHAD FOREIGN KEY REFERENCES TORGNY (REFERENCES DNA MOMENT MARY WEC G DECIMAIS COCIMAL DECIMALIA MCDOWALS WECO FORDONKEY COREFERENCES CREATE TABLE Does DUO INCREMENT PRMANY P DATE Dugan D Tata TEXT FORDONKEY OFFENCES CREATE TABLE CREATE TABLE eaten AUTO INCREMENT PRIMARY KEY. St End W Cum ARCHA FOREIGN KEY (Patient REFERENCES P CREATE TABLE DNT AUTO INCREMENT PRIMARY VARCHAR Преспавлявал масн Departe ICHARITOO Contact Info WOWRIS CHEAT TABLE Appointments Apport DIN AUTONEMENT PRIMARY D INT Doctor D INT Aparent DevCATE Explain these in detail and why you used this IN NIO Nine, Age, Gender, Address Contact Medical Hond HALLES Ca 30 M. 10th St. 555 123, atory of meer 22 F20 Street, 555-5678 Noagnificant cal INSERT INTO Test, on est Te Narel VALUES гово Tog bom test 0 Det type D R VALUES 112024-12-15, 1, N…arrow_forwardI need help with this problem, and an explanation for the solution is described below (Fundamentals of Computer Engineering: ModelSim - standard edition). I need help fixing errors on the VHDL so that the counter counts up from 1 to 7 of both files, as the attached image shows when compiled. Counter_1_to_7.vhdl: library IEEE; use IEEE.STD_LOGIC_1164.ALL; use IEEE.STD_LOGIC_ARITH.ALL; use IEEE.STD_LOGIC_UNSIGNED.ALL; entity Counter_1_to_7 is Port ( clk : in STD_LOGIC; -- Clock input reset : in STD_LOGIC; -- Asynchronous reset count : out STD_LOGIC_VECTOR (2 downto 0) -- 3-bit output (1 to 7) ); end Counter_1_to_7; architecture Behavioral of Counter_1_to_7 is signal counter_reg : STD_LOGIC_VECTOR (2 downto 0) := "001"; -- Start at 1 begin process(clk, reset) begin if reset = '1' then counter_reg <= "001"; -- Reset to 1 elsif rising_edge(clk) then if counter_reg = "111" then counter_reg <= "001"; -- Wrap around to 1 after 7 else counter_reg <= counter_reg + 1; -- Increment…arrow_forwardTasks 4 • • . • • Task 1: Create a 'Movie' class and update its rating using keyword arguments. Task 2: Create a 'Student' class and change the major using positional and keyword arguments. Task 3: Create a 'ShoppingCart' class and add items using positional arguments. 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Task 5(homework): Create a 'Library' class and return a new library object with added books.arrow_forwardTasks 6 • Task 1: Develop a StudentProfile` class with private attributes for `name` and _ grades` (a list of grades), and methods to add a grade and calculate the average. • Task 2: Create a `Playlist class that stores song titles in a private list, with methods to add a song, remove a song, and display the current playlist. • Task 3: Implement a Temperature Sensor` class with a private `_temperature attribute, and methods to set and get the temperature in both Celsius and Fahrenheit. • • Task 4: Build a Library Book class with private attributes for the title and availability status; include methods to check out, return, and display the book's availability Task 5(homework): Create a 'Counter class with a private _ count attribute, and include get_count()` and `set_count(value)` methods to access and modify it. Ensure set_count only accepts non-negative integers, and add increment()', decrement()', and 'reset()` methods for control.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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