Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
5th Edition
ISBN: 9780124077263
Author: David A. Patterson, John L. Hennessy
Publisher: Elsevier Science
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Expert Solution & Answer
Chapter 1, Problem 1.8.2E
Explanation of Solution
Given,
The Pentium 4 Prescott processor includes 3.6 GHz of frequency and 1.25 V of voltage with 10 W and 90 W of static power and dynamic power respectively.
The Core i5 Ivy Bridge processor includes 3.4 GHz of frequency and 0.9 V of voltage with 30 W and 40 W of static power and dynamic power respectively.
The percentage of dissipated power comprised by static power of the processor can be calculated using the following formula
Substitute, “10” for “static power” and “90” for “dynamic power” is given below:
Expert Solution & Answer
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Taylor Series Approximation Example- H.W
More terms used implies better approximation
f(x)+
f(x)
Zero order
First order
1.0
0.5
x-0
Second order
True
f(x) f(x)
• flx;+ 1) = f(x) + fƒ '\x;}h
√(x,+ 1) = f(x) + f (x)h + "(x) 2
f(x1)
X+1-1
f(x) 0.1x 0.15x³-0.5x²-0.25x+1.2
Taylor Series Approximation H.w:
Smaller step size implies smaller error
Errors
100+
F(x)
Zero order
First order
Second order
0.5
Reduced step size
0
x, 0
f(x+1)f(x,) + ƒ\x,}h
51
f(x + 1) − f(x) + (x)+2
((x1)
+1-1
Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5
iterations (or & s= 5%) for
f(x) 0.1x 0.15x³-0.5x2- 0.25x+1.2
マ
52
Home Work
Use Taylor's series expansion to Compute the true and approximate percent relative
errors & and εa for x = π/6, use 6 iterations for the series.
sin(x)
== x-
Taylor Series Approximation Example- H.W
More terms used implies better approximation
f(x) 4
f(x)
Zero order
f(x + 1) = f(x;)
First order
f(x; + 1) = f(x;) + f'(x;)h
1.0
Second order
0.5
True
f(x + 1) =
f(x) + f'(x)h +
ƒ"(x;)
h2
2!
f(x+1)
0
x; = 0
x+1 = 1
x
h
f(x)=0.1x4-0.15x³- 0.5x2 -0.25x + 1.2
51
Taylor Series Approximation H.w:
Smaller step size implies smaller error
Errors
f(x) +
f(x,)
Zero order
f(x,+ 1) = f(x)
First order
1.0
0.5
Reduced step size
Second order
True
f(x + 1) = f(x) + f'(x)h
f(x; + 1) = f(x) + f'(x)h + "(xi) h2
f(x,+1)
O
x₁ = 0
x+1=1
Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5
iterations (or & s= 5%) for
f(x)=0.1x 0.15x³-0.5x²- 0.25x + 1.2
52
Chapter 1 Solutions
Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
Ch. 1 - Prob. 1.1ECh. 1 - Prob. 1.2ECh. 1 - Prob. 1.3ECh. 1 - Prob. 1.4ECh. 1 - Prob. 1.5ECh. 1 - Prob. 1.6ECh. 1 - Prob. 1.7ECh. 1 - Prob. 1.8.1ECh. 1 - Prob. 1.8.2ECh. 1 - Prob. 1.8.3E
Ch. 1 - Prob. 1.9.1ECh. 1 - Prob. 1.9.2ECh. 1 - Prob. 1.9.3ECh. 1 - Prob. 1.10.1ECh. 1 - Prob. 1.10.2ECh. 1 - Prob. 1.10.3ECh. 1 - Prob. 1.10.4ECh. 1 - Prob. 1.11.1ECh. 1 - Prob. 1.11.2ECh. 1 - Prob. 1.11.3ECh. 1 - Prob. 1.11.4ECh. 1 - Prob. 1.11.5ECh. 1 - Prob. 1.11.6ECh. 1 - Prob. 1.11.7ECh. 1 - Prob. 1.11.8ECh. 1 - Prob. 1.11.9ECh. 1 - Prob. 1.11.10ECh. 1 - Prob. 1.11.11ECh. 1 - Prob. 1.12.1ECh. 1 - Prob. 1.12.2ECh. 1 - Prob. 1.12.3ECh. 1 - Prob. 1.12.4ECh. 1 - Prob. 1.13.1ECh. 1 - Prob. 1.13.2ECh. 1 - Prob. 1.13.3ECh. 1 - Prob. 1.14.1ECh. 1 - Prob. 1.14.2ECh. 1 - Prob. 1.14.3ECh. 1 - Prob. 1.15E
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