Computer Organization and Design MIPS Edition, Fifth Edition: The Hardware/Software Interface (The Morgan Kaufmann Series in Computer Architecture and Design)
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Chapter 1, Problem 1.12.3E

Explanation of Solution

Given,

The processor P1 includes clock rate of 4 GHz with 0.9 Cycles Per Instructions (CPI) and requires 5×109 number of instructions.

The processor P2 includes clock rate of 3 GHz with 0.75 CPI and requires 1×109 number of instructions.

The time taken by the processor to complete the process can be calculated using the following formula is given below:

Time taken=Numberofinstructions×CPIClockrate

Substitute, “5×109” for “Number of instructions”, “0.9” for “CPI” and “4×109” for “clock rate” in the above formula is given below:

T(P1)=5×109×0.94×109=1.125

Thus, the time required by the processor P1 is 1.125 seconds.

Substitute, “1×109” for “Number of instructions”, “0.75” for “CPI” and “3×109” for “clock rate” in the above formula is given below:

T(P2)=1×109×0.753×109=0.25

Thus, the time required by the processor P2 is 0.25 seconds.

The Millions of Instructions Per Second (MIPS) of the processor can be calculated using the following formula is given below:

MIPS=Clockrate×10-6CPI

Substitute, “0

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