Chapter 1, Problem 1.19P

Interpretation Introduction

Interpretation:

Maximum height that is achieved by $\text{0}\text{.500}\text{kg}$ stone that is thrown upward with a speed of $55\text{m}\cdot {\text{s}}^{-1}$ has to be calculated.

Concept Introduction:

Energy that is associated with a moving object is known as kinetic energy.  The energy that is possessed by an object due to its location that is related to a specific reference is known as potential energy.  Kinetic energy of any object is expressed by the equation shown below.

    $E_k=\frac{1}{2}m{v}^2$

Where $E_k$ is kinetic energy, $m$ is the mass of object, and $v$ is the velocity of object.

Potential energy for an object that is located above the ground level can be expressed by an equation given below.

    $E_p=mgh$

Where $E_p$ is the potential energy, $g$ is the proportionality constant that is equal to $9.81\text{m}\cdot {\text{s}}^{-2}$, $m$ is mass of object and $h$ is the height from ground level.