From a set of n people, a committee of size j is to be chosen, and from this committee, a subcommittee of size i , i ≤ j , is also to be chosen. a. Derive a combinational identity by computing, in two ways, the number of possible choices of the committee and subcommittee—first by supposing that the committee is chosen first and then the subcommittee is chosen, and second by supposing that the subcommittee is chosen first and then the remaining members of the committee are chosen. b. Use part (a) to prove the following combinatorial identity: ∑ j = 1 n ( n j ) ( j i ) = ( n i ) 2 n − i i ≤ n c. Use part (a) and Theoretical Exercise 13 to show that ∑ j = 1 n ( n j ) ( j i ) ( − 1 ) n − j = 0 i < n
From a set of n people, a committee of size j is to be chosen, and from this committee, a subcommittee of size i , i ≤ j , is also to be chosen. a. Derive a combinational identity by computing, in two ways, the number of possible choices of the committee and subcommittee—first by supposing that the committee is chosen first and then the subcommittee is chosen, and second by supposing that the subcommittee is chosen first and then the remaining members of the committee are chosen. b. Use part (a) to prove the following combinatorial identity: ∑ j = 1 n ( n j ) ( j i ) = ( n i ) 2 n − i i ≤ n c. Use part (a) and Theoretical Exercise 13 to show that ∑ j = 1 n ( n j ) ( j i ) ( − 1 ) n − j = 0 i < n
From a set of n people, a committee of size j is to be chosen, and from this committee, a subcommittee of size
i
,
i
≤
j
, is also to be chosen.
a. Derive a combinational identity by computing, in two ways, the number of possible choices of the committee and subcommittee—first by supposing that the committee is chosen first and then the subcommittee is chosen, and second by supposing that the subcommittee is chosen first and then the remaining members of the committee are chosen.
b. Use part (a) to prove the following combinatorial identity:
∑
j
=
1
n
(
n
j
)
(
j
i
)
=
(
n
i
)
2
n
−
i
i
≤
n
c. Use part (a) and Theoretical Exercise 13 to show that
∑
j
=
1
n
(
n
j
)
(
j
i
)
(
−
1
)
n
−
j
=
0
i
<
n
13) Consider the checkerboard arrangement shown below. Assume that the red checker can move diagonally
upward, one square at a time, on the white squares. It may not enter a square if occupied by another checker, but
may jump over it. How many routes are there for the red checker to the top of the board?
12) The prime factors of 1365 are 3, 5, 7 and 13. Determine the total number of divisors of 1365.
11) What is the sum of numbers in row #8 of Pascal's Triangle?
Elementary Algebra For College Students (10th Edition)
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